The attached question's answer is E. Can anyone solve and explain?? (I am not good at math...)
Thank you for your help!
R.
Can you help? - question from OG10th
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Put 4 in the Thousand's place
Then the remaining 3 numbers can be arranged in 3! ways = 6
So there are 6numbers of 4xxxx which means a min value of 24,000
Similarly for 3 6x3 = 18000
For 2 = 12,000
For 1 = 6000
So a minimum value of 24+18+12+6 = 60,000
Remember that you still havent added the other numbers i.e. in the 4000 series you didnt add the value of 321 + 123+132+...
So your final answer has to be E 66,660
Then the remaining 3 numbers can be arranged in 3! ways = 6
So there are 6numbers of 4xxxx which means a min value of 24,000
Similarly for 3 6x3 = 18000
For 2 = 12,000
For 1 = 6000
So a minimum value of 24+18+12+6 = 60,000
Remember that you still havent added the other numbers i.e. in the 4000 series you didnt add the value of 321 + 123+132+...
So your final answer has to be E 66,660
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guys,
i found another way of solving it...
tell me if it is wrong, please
so
each combitation has 6 ways of starting with 1, 2, 3, 4
if we multiply and then add just thousands- 6*2, 6*1, 6*3, 6*4, we get in sum 60,
the D answer is 60000 but we know that it will be more than 60000 cause we just added the thousands and left hundreds tens etc
so it has to be E.
i found another way of solving it...
tell me if it is wrong, please
so
each combitation has 6 ways of starting with 1, 2, 3, 4
if we multiply and then add just thousands- 6*2, 6*1, 6*3, 6*4, we get in sum 60,
the D answer is 60000 but we know that it will be more than 60000 cause we just added the thousands and left hundreds tens etc
so it has to be E.
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kandelaki - that's the most efficient way to do it - nice job!
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