in how many different ways can a group of 8 people be divided into 4 teams of 2 people each?
105
different ways
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to arrange 8 people is 8!
Divided by 4 group of 2 people 4! x 2! x 2! x 2! x 2!
= (8 x 7x 6 x 5 x 4!) / (4! x 2! x 2! x 2! x 2!)
= 7 x 3 x 5
= 105
Divided by 4 group of 2 people 4! x 2! x 2! x 2! x 2!
= (8 x 7x 6 x 5 x 4!) / (4! x 2! x 2! x 2! x 2!)
= 7 x 3 x 5
= 105
Last edited by imnlovwithstripper on Mon Apr 27, 2009 5:53 pm, edited 1 time in total.
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You have the following options of 8 teams divided into 4 teams of 2 persons:
-- -- -- --
1st -- = can be arranged in 8*7 ways and the order can be (AB or BA) so 2 ways of arranging them
2nd -- = can be arranged in 6*5 ways and the order can be (CD or DC) so 2 ways of arranging them
3rd -- = can be arranged in 4*3 ways and the order can be (EF or FE) so 2 ways of arranging them
4th -- = can be arranged in 2*1 way and the order can be (GH or HG) so 2 ways of arranging them
Also then 4 groups can be arranged in 4! ways like
ABCDEFGH
ABCDEFHG and etc in 4! ways
So total = 8!/(4!*2!*2!*2!*2!) = 105
-Deepak
-- -- -- --
1st -- = can be arranged in 8*7 ways and the order can be (AB or BA) so 2 ways of arranging them
2nd -- = can be arranged in 6*5 ways and the order can be (CD or DC) so 2 ways of arranging them
3rd -- = can be arranged in 4*3 ways and the order can be (EF or FE) so 2 ways of arranging them
4th -- = can be arranged in 2*1 way and the order can be (GH or HG) so 2 ways of arranging them
Also then 4 groups can be arranged in 4! ways like
ABCDEFGH
ABCDEFHG and etc in 4! ways
So total = 8!/(4!*2!*2!*2!*2!) = 105
-Deepak
- dumb.doofus
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Just another way I thought about the solution
Number of ways of selecting 2 people from 8 = 8C2
Number of ways of selecting 2 people from 6 = 6C2
Number of ways of selecting 2 people from 4 = 4C2
Number of ways of selecting 2 people from 2 = 2C2
Total number of way of selecting 4 teams = 8C2x6C2x4C2x2C2 --- (1)
Number of ways these 4 teams can be arranged is 4! ---- (2)
so total number of distinct ways = (1)/(2)
= 105
Number of ways of selecting 2 people from 8 = 8C2
Number of ways of selecting 2 people from 6 = 6C2
Number of ways of selecting 2 people from 4 = 4C2
Number of ways of selecting 2 people from 2 = 2C2
Total number of way of selecting 4 teams = 8C2x6C2x4C2x2C2 --- (1)
Number of ways these 4 teams can be arranged is 4! ---- (2)
so total number of distinct ways = (1)/(2)
= 105
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could someone explain why it matters how many different ways the 4 teams can be arranged?
It seems like all that matters is the distribution of the people among teams and not the order of the teams .. or the order of the people on the teams for that matter ..
Thanks for the help in advance.
It seems like all that matters is the distribution of the people among teams and not the order of the teams .. or the order of the people on the teams for that matter ..
Thanks for the help in advance.