If 53 students are enrolled in both the CS103 (Algorithms and Data Structures) and the M101 (Mathematics for Computer Science) classes. How many of the CS103 students are not enrolled in M101?
(1) 72 students are taking the M101
(2) 59 students are taking the CS103
OA after
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CS103 and M101
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bluementor
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Stmt 1: No info on CS103 participation. Insufficient.
Stmt 2: CS103_total = 59 = CS103_only + Both. Both is given, so statement 2 is suffcient.
Choose B.
-BM-
Stmt 2: CS103_total = 59 = CS103_only + Both. Both is given, so statement 2 is suffcient.
Choose B.
-BM-
Statement 2 is definitely sufficient to answer the question.
if 59 students are enrolled in arithmetic and 53 are enrolled in both courses, that means 53 of the 59 are enrolled in Mathematics, thus 6 are not.
if 59 students are enrolled in arithmetic and 53 are enrolled in both courses, that means 53 of the 59 are enrolled in Mathematics, thus 6 are not.
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4meonly
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Guys,4meonly wrote:why we chould not take into count those students who are NOT involved in any class?
I know the OA. The question is why answer is B?
We do not know the total number of students and the number of students that are enrolled only in M101. That's why I think answer is E.
What do you think?
Can anybody post exhaustive reasoning?
Thank you!
4meonly wrote:why we chould not take into count those students who are NOT involved in any class?
Because in the question you are asked "How many of the CS103 students are not enrolled in M101?" To answer this question you need only CS103 size and how many students are in both CS103 and M101 classes. The second is given in the stem, so you are looking only for CS103 size.
In 1 you don't know how many people are in CS103, so even when you know that M101 has 72 students you have no way of knowing how many of the CS103 students are not enrolled. so 1 //insuff
In 2 we know that 59 students are taking the CS103 class. From the stem we also know that 53 students take both CS103 and M101 classes. So 6 students from CS103 are not taking M101, hence //sufficient
Answer B.
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sanju09
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Where did you get this image from, friend? 72 should be the total number of students taking M101, not M101 only. Though it doesn't help much.4meonly wrote:Guys,4meonly wrote:why we chould not take into count those students who are NOT involved in any class?
I know the OA. The question is why answer is B?
We do not know the total number of students and the number of students that are enrolled only in M101. That's why I think answer is E.
What do you think?
Can anybody post exhaustive reasoning?
Thank you!
By the way IMO B.
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
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maihuna
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c and m 534meonly wrote:If 53 students are enrolled in both the CS103 (Algorithms and Data Structures) and the M101 (Mathematics for Computer Science) classes. How many of the CS103 students are not enrolled in M101?
(1) 72 students are taking the M101
(2) 59 students are taking the CS103
OA after
c total 59 which includes the 53 taking m as well, so 6 not enrolled for m
