In the figure, points P and Q lie on the circle with center O. What is the value of S?
a) 1/2
b) 1
c) SQRT2
d) SQRT3
e) SQRT2 / 2
Crazyy
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- Patrick_GMATFix
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Nice job live2win.
This one is very tough, but tests whether you realize that:
1) OP = OQ. and
2) If you drew a line straight down from P to the x-axis, you would form a triangle of base 1 and height root(3), so it will be a 30-60-90 triangle.
The angle measures are key because from them you can deduce a lot about s and t. it's tough to explain without drawings but the answer is B.
Have a look at a detailed solution, including a video solution: this is GMATprep question 1082
-Patrick
This one is very tough, but tests whether you realize that:
1) OP = OQ. and
2) If you drew a line straight down from P to the x-axis, you would form a triangle of base 1 and height root(3), so it will be a 30-60-90 triangle.
The angle measures are key because from them you can deduce a lot about s and t. it's tough to explain without drawings but the answer is B.
Have a look at a detailed solution, including a video solution: this is GMATprep question 1082
-Patrick
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Ii couldn't solve this Q. I got as far as recognizing that the radii must be equal, but I focused on trying to find the length of PQ. The video solution is really helpful. Thanks!
- albatross86
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Slope of line OP = -1/sqrt(3)
So, slope of line OQ = sqrt(3) = t/s
so t = sqrt(3)*s
OP = 2 = OQ
OQ = sqrt(s^2 + t^2)
= sqrt(s^2 + 3*s^2)
= 2s
So 2s = 2
=> s = 1
So, slope of line OQ = sqrt(3) = t/s
so t = sqrt(3)*s
OP = 2 = OQ
OQ = sqrt(s^2 + t^2)
= sqrt(s^2 + 3*s^2)
= 2s
So 2s = 2
=> s = 1
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You can also use the distance formula to calculate PO. Given that 2 radii are the same and 90 degrees in the middle = 45 45 90 .. - Hypotenuse = PO*SQRT (2). Then you can use S-P = PO*SQRT(2)
and knowing sqrt of 2 ~ 1.4. you can estimate
and knowing sqrt of 2 ~ 1.4. you can estimate