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GmatKiss GMAT Titan Default Avatar
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Consulting Post Mon May 21, 2012 7:19 am
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    ABC Consulting charges more for the first 100 man-hours of a project than for additional hours beyond the first 100. If Acme’s fees for using ABC Consulting’s services were $14,000, how many man-hours were charged?

    (1) ABC Consulting charges $100 per man-hour for the first 100 man-hours and $80 per man-hour for each additional hour or fraction of an hour.
    (2) If the charges for the first 100 hours had been $120/man-hour, Acme’s total consulting charges would have been $16,000.

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    Stuart Kovinsky GMAT Instructor
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    Post Mon May 21, 2012 1:25 pm
    GmatKiss wrote:
    ABC Consulting charges more for the first 100 man-hours of a project than for additional hours beyond the first 100. If Acme’s fees for using ABC Consulting’s services were $14,000, how many man-hours were charged?

    (1) ABC Consulting charges $100 per man-hour for the first 100 man-hours and $80 per man-hour for each additional hour or fraction of an hour.
    (2) If the charges for the first 100 hours had been $120/man-hour, Acme’s total consulting charges would have been $16,000.
    Hi!

    From the stem, we know that the fee is $x/hour for the first 100 hours and $y/hour for extra hours. We also know that Acme was charged a total of $14000. So, we can create the following formula:

    100*$x + (n-100)*$y = $14000

    (n = total number of hours charged)

    and the question is "what's the value of n?".

    Note: we don't know that Acme was charged for more than 100 hours (never make assumptions in DS!), so if n<100 then we just ignore the second term in the equation.

    To the statements!

    1) x=100 and y=80. So:

    100*$100 + (n-100)*$80 = $14000

    One variable, bunch of numbers: sufficient... eliminate B, C and E.

    2) if x=120, then total = 16000. So:

    100*$120 + (n-100)*$y = $16000

    Simplifying:

    (n-100)*$y = $4000

    Two variables, only one equation: insufficient.. eliminate D. Choose A!

    Now we could have saved time by using the most powerful DS rule: number of equations vs number of unknowns. Always remember:

    To solve for a system of n variables, you require n distinct and linear equations

    While there are a number of important exceptions to the rule, looking for opportunities to apply it to DS questions will save you a LOT of valuable time as you avoid calculations.

    From the stem: 1 equation, 3 unknowns. Missing: 2 distinct linear equations.

    1) 2 distinct linear equations; no new variables: sufficient!
    2) 1 distinct linear equation; doesn't get rid of both unwanted variables in one shot: insufficient!

    (1) is suff, (2) isn't: choose A!

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