If x, y, and z are negative integers and 3x - 3y = -3z, then which of the following statements must be true?
I. x > y
II. x > y > z
III. x = z
A I and II
B I only
C II only
D III only
E None
OA Later.... first some discussions..
Confusing PS
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Hi,
3x - 3y = -3z => x+z = y
As, x,y,z are negative. y should be smaller than x and z.
eg: if x = -2, z=-3, y = -5.
The relation between x and z cannot be established though.
y<x and y<z
Hence, B
3x - 3y = -3z => x+z = y
As, x,y,z are negative. y should be smaller than x and z.
eg: if x = -2, z=-3, y = -5.
The relation between x and z cannot be established though.
y<x and y<z
Hence, B
Cheers!
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Things are not what they appear to be... nor are they otherwise
- Gurpinder
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3x - 3y = -3z
simplify the equation first to ->> x - y = -z -->
x = -z + y ..... since the integers are negative....lets see what it would look like in real....x(-1) = -z(-1) + y(-1)
-x = z - y
x = -z + y <---- equation withouting worrying about plugging in negative numbers now.
Clearly here y > x, hence A,B is out
If the above is false, then so is D.
We are left with C and E.
C is also false because x does not = z.
IMO E
Let me know if I went wrong some where....
simplify the equation first to ->> x - y = -z -->
x = -z + y ..... since the integers are negative....lets see what it would look like in real....x(-1) = -z(-1) + y(-1)
-x = z - y
x = -z + y <---- equation withouting worrying about plugging in negative numbers now.
Clearly here y > x, hence A,B is out
If the above is false, then so is D.
We are left with C and E.
C is also false because x does not = z.
IMO E
Let me know if I went wrong some where....
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Yes Frank is right.. The answer is B.
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Hi,Gurpinder wrote:@ Frank
Where did I go wrong?
-x = z - y
x = -z + y <---- equation withouting worrying about plugging in negative numbers now.
Clearly here y > x, hence A,B is out
-z is positive. So, when you add a positive quantity(-z) to a negative quantity(y), the resulting number(x) will increase. So, x > y
eg. -2 = 3 + (-5). Here x = -2, z= -3, y =-5
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- vikram4689
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Well this is NOT so confusing, did it in 60sec, apply it this way
3x -3y = -3z
x - y = -z
x + z = y .... This is the equation we need to evaluate.
Since all are -ve, y will always be more -ve than x and hence x > y
from equation you can easily say that II & III are not essentially true.
Bingo!! Answer is B.
3x -3y = -3z
x - y = -z
x + z = y .... This is the equation we need to evaluate.
Since all are -ve, y will always be more -ve than x and hence x > y
from equation you can easily say that II & III are not essentially true.
Bingo!! Answer is B.
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- Gurpinder
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Ahh...I confused my self....Frankenstein wrote:Hi,Gurpinder wrote:@ Frank
Where did I go wrong?
-x = z - y
x = -z + y <---- equation withouting worrying about plugging in negative numbers now.
Clearly here y > x, hence A,B is out
-z is positive. So, when you add a positive quantity(-z) to a negative quantity(y), the resulting number(x) will increase. So, x > y
eg. -2 = 3 + (-5). Here x = -2, z= -3, y =-5
yes, y=x+z and since they are negative, x>y
thanks buddy!
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
- Alfred A. Montapert, Philosopher.