what is the following equal to?
sqrt [ 2xsqrt(63) + 2/(8 + 3xsqrt(7) ) ]
the answer isn't as important as to find a way to quickly solve this. I know there is a trick, but i can't seem to find it.
thanks
Complicated formula
This topic has expert replies
Answer is 4. I don't see a shorter way to solve this then by figuring out like terms, and then rationalizing the denominator.
Step 1: Look at what is on the inside. 2*sqrt(63) can be rewritten as 6*sqrt(7), and when you add that to 2/(8+3*sqrt(7)), you need to have a common denominator or 8+3*sqrt(7).
Step 2: from step 1, you will get the following term:
[(6*sqrt(7)*(8+3*sqrt(7)) + 2]/(8+3*sqrt(7))
This comes out to (48*sqrt(7) + 128)/(8+3*sqrt(7)).
Step 3: Now you need to rationalize denominator, so multiply both the numerator and denominator by (8-3*sqrt(7)).
This gives you (48*sqrt(7) + 128)*(8 - 3*sqrt(7)) / 1. You get 1 in the denominator after the rationalization (8+3*sqrt(7))*(8-3*sqrt(7)) = 64 - 3*3*7 = 64 - 63 = 1
Step 4: Doing in the arithmetic in the numerator will give you a numerator of 16 (go carefully). So final step is that you have square root over the entire term, so sqrt(16) = 4.
Step 1: Look at what is on the inside. 2*sqrt(63) can be rewritten as 6*sqrt(7), and when you add that to 2/(8+3*sqrt(7)), you need to have a common denominator or 8+3*sqrt(7).
Step 2: from step 1, you will get the following term:
[(6*sqrt(7)*(8+3*sqrt(7)) + 2]/(8+3*sqrt(7))
This comes out to (48*sqrt(7) + 128)/(8+3*sqrt(7)).
Step 3: Now you need to rationalize denominator, so multiply both the numerator and denominator by (8-3*sqrt(7)).
This gives you (48*sqrt(7) + 128)*(8 - 3*sqrt(7)) / 1. You get 1 in the denominator after the rationalization (8+3*sqrt(7))*(8-3*sqrt(7)) = 64 - 3*3*7 = 64 - 63 = 1
Step 4: Doing in the arithmetic in the numerator will give you a numerator of 16 (go carefully). So final step is that you have square root over the entire term, so sqrt(16) = 4.
mp2437 wrote:Answer is 4. I don't see a shorter way to solve this then by figuring out like terms, and then rationalizing the denominator.
Step 1: Look at what is on the inside. 2*sqrt(63) can be rewritten as 6*sqrt(7), and when you add that to 2/(8+3*sqrt(7)), you need to have a common denominator or 8+3*sqrt(7).
Step 2: from step 1, you will get the following term:
[(6*sqrt(7)*(8+3*sqrt(7)) + 2]/(8+3*sqrt(7))
This comes out to (48*sqrt(7) + 128)/(8+3*sqrt(7)).
Step 3: Now you need to rationalize denominator, so multiply both the numerator and denominator by (8-3*sqrt(7)).
This gives you (48*sqrt(7) + 128)*(8 - 3*sqrt(7)) / 1. You get 1 in the denominator after the rationalization (8+3*sqrt(7))*(8-3*sqrt(7)) = 64 - 3*3*7 = 64 - 63 = 1
Step 4: Doing in the arithmetic in the numerator will give you a numerator of 16 (go carefully). So final step is that you have square root over the entire term, so sqrt(16) = 4.
Thank you. but don't you think there has to be a faster way? step 4 takes forever to do, there has to be a trick that will help solve step 4 in a fast way. any thoughts anyone?