During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played?
G= games
(.80)(100) +.50(G-100)= .70G
I don't understand how the second 100 is included in the equation. Can I have an experts help?
Thank-you!
Beth
Algebra - Percents
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If we let G = the TOTAL number of games played in the ENTIRE SEASON, then ...During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played?
(A) 180
(B) 170
(C) 156
(D) 150
(E) 105
G - 100 = the number of games REMAINING after the first 100 have been played
We can now start with a "word equation":
(# of wins in 1st 100 games) + (# of wins in remaining games) = (# of wins in ENTIRE season)
We get: (80% of 100) + (50% of G-100) = 70% of G
Rewrite as 80 + 0.5(G - 100) = 0.7G
Expand: 80 + 0.5G - 50 = 0.7G
Simplify: 30 = 0.2G
Solve: G = 150
Answer: D
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Hi Beth,
The algebra involved in this question can be written out in a couple of different ways. Here's a slightly different variation:
We're told that a team won 80% of its first 100 games and 50% of the remaining games
Initial wins = .8(100) = 80
Later wins = .5(X) = .5X
Total wins = 80 + .5X
Total games played: (100+X)
We're also told that the team won 70% of the games that it played for the ENTIRE SEASON. We now how 2 different pieces of information that mean the same thing, so we can set them equal to one another....
Total wins = .7(100+X)
Total wins = 80 + .5X = .7(100+X)
From here, we have a 1 variable and 1 equation, so we CAN solve for X.
GMAT assassins aren't born, they're made,
Rich
The algebra involved in this question can be written out in a couple of different ways. Here's a slightly different variation:
We're told that a team won 80% of its first 100 games and 50% of the remaining games
Initial wins = .8(100) = 80
Later wins = .5(X) = .5X
Total wins = 80 + .5X
Total games played: (100+X)
We're also told that the team won 70% of the games that it played for the ENTIRE SEASON. We now how 2 different pieces of information that mean the same thing, so we can set them equal to one another....
Total wins = .7(100+X)
Total wins = 80 + .5X = .7(100+X)
From here, we have a 1 variable and 1 equation, so we CAN solve for X.
GMAT assassins aren't born, they're made,
Rich
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Of course, another (possibly super fast) approach it to check the answer choices.During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played?
(A) 180
(B) 170
(C) 156
(D) 150
(E) 105
ADDED BONUS: The total number of wins must be an INTEGER. Since 70% of 156 and 70% of 105 both result in non-integer values for the total number of wins, we need not consider them.
Test answer choice A
Given: the team won 80% of its first 100 games. So, it won 80 games.
If there is a TOTAL of 180 games, then there are 80 games remaining.
The team won 50% of its remaining games. 50% of 80 = 40 wins
80 wins + 40 wins = a TOTAL of 120 wins
Now compare this result with the part about winning 70% of all games.
If there is a TOTAL of 180 wins, then the total number of wins = 70% of 180 = 156 wins
Doesn't match up - ELIMINATE A
.
.
.
Test answer choice D
Given: the team won 80% of its first 100 games. So, it won 80 games.
If there is a TOTAL of 150 games, then there are 50 games remaining.
The team won 50% of its remaining games. 50% of 50 = 25 wins
80 wins + 25 wins = a TOTAL of 105 wins
Now compare this result with the part about winning 70% of all games.
If there is a TOTAL of 150 wins, then the total number of wins = 70% of 150 = 105 wins
PERFECT!
Answer: D
Cheers,
Brent
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We can also use the trusty number line. The team won 80% of its first 100 games, 50% of the remaining games, and 70% of the total. On the number line, it will look like this:
Notice that the ratio of the remaining games to the first 100 games will be 10:20, or 1:2. That means that the number of remaining games is 1/2 the first 100 games, or 50. 100 + 50 = 150.
Notice that the ratio of the remaining games to the first 100 games will be 10:20, or 1:2. That means that the number of remaining games is 1/2 the first 100 games, or 50. 100 + 50 = 150.
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Note also, that this problem could have been written as, "We have 100 liters of solution x, which is 80% alcohol. If we added solution y, which is 50% alcohol, to solution x, and ended up with a combined solution that was 70% alcohol, how many liters of the combined solution would we have?" Whether we're talking about baseball games or solutions, the math/logic is the same.
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Solution:[email protected] wrote:During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played?
G= games
(.80)(100) +.50(G-100)= .70G
I don't understand how the second 100 is included in the equation. Can I have an experts help?
Thank-you!
Beth
We are first given that a team won 80 percent of its first 100 games. Thus, the team won 0.8 x 100 = 80 games out of its first 100 games.
We are next given that the team won 50 percent of its remaining games. If we use variable T to represent the total number of games in the season, then we can say (T - 100) equals the number of remaining games in the season. Thus, we can say:
0.5(T - 100) = number of wins for remaining games
0.5T - 50 = number of wins for remaining games
Lastly, we are given that team won 70 percent of all games played in the season. That is, they won 0.7T games in the entire season. With this we can set up the equation:
Number of games won from first 100 games + Number of games won from the remaining games = Total Number of games won in the entire season
80 + (0.5T - 50) = 0.7T
30 + 0.5 T = 0.7T
30 = 0.2T
300 = 2T
150 = T
Answer: D
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80/100 + 50(r-100)/100 = 70r/100
cancelling 100
8000 + 50(r-100)= 70r
8000-5000 + 50r = 70r
3000 = 20 r
r = 150
Answer D
cancelling 100
8000 + 50(r-100)= 70r
8000-5000 + 50r = 70r
3000 = 20 r
r = 150
Answer D