Tom is on a certain diet that requires him to limit the number of calories he takes in each day. He is allowed to take in 2400 calories each day from three square meals, and 200 calories each day from snacks and dessert combined. On some days, he splurges by taking in three times the recommended number of calories from snacks and dessert. The rest of the days, he follows the calorie guidelines precisely. If his average calorie intake for a 10 day period was 2720, on how many days did he splurge?
A. 3
B. 4
C. 5
D. 6
E. 7
Am I solving this correctly? I haven't seen this approach online.
10(days)*2,720(ave per day)=27,200
2400(10 days)+200X=27,200
24,000+200X=27,200
200X=3200
X=16
16 (total snacks) -10 (total days) = 6 (extra snacks consumed)
6/2(he takes 3 times the recommended calories, I already included 1 time in the above equation, therefore I divide by 2) = 3
Is my approach correct?
This topic has expert replies
GMAT/MBA Expert
- [email protected]
- Elite Legendary Member
- Posts: 10392
- Joined: Sun Jun 23, 2013 6:38 pm
- Location: Palo Alto, CA
- Thanked: 2867 times
- Followed by:511 members
- GMAT Score:800
Hi aces021,
Yes, your math is correct. It's worth noting that there are several ways to "do the math" in this question OR you could TEST THE ANSWERS instead of doing lots of calculations. Here's how:
We're told that the average for 10 days was 2720 calories, so the total number of calories is 2720 x 10 = 27,200
We're told that...
on a normal day, Tom eats 2400+200 calories = 2600 calories
on a splurge day, Tom easts 2400 + 600 calories = 3000 calories
We're asked for the number of splurge days.
Let's TEST THE ANSWERS...
Answer B = 4.
4 splurge days = 4 x 3000 = 12,000
6 normal days = 6 x 2600 = 15,600
Total Calories = 27,600
This is TOO MANY CALORIES (we're supposed to have 27,200), so this answer has TOO MANY splurge days.
The only answer that would give us fewer calories is answer A. This must be the correct answer.
GMAT assassins aren't born, they're made,
Rich
Yes, your math is correct. It's worth noting that there are several ways to "do the math" in this question OR you could TEST THE ANSWERS instead of doing lots of calculations. Here's how:
We're told that the average for 10 days was 2720 calories, so the total number of calories is 2720 x 10 = 27,200
We're told that...
on a normal day, Tom eats 2400+200 calories = 2600 calories
on a splurge day, Tom easts 2400 + 600 calories = 3000 calories
We're asked for the number of splurge days.
Let's TEST THE ANSWERS...
Answer B = 4.
4 splurge days = 4 x 3000 = 12,000
6 normal days = 6 x 2600 = 15,600
Total Calories = 27,600
This is TOO MANY CALORIES (we're supposed to have 27,200), so this answer has TOO MANY splurge days.
The only answer that would give us fewer calories is answer A. This must be the correct answer.
GMAT assassins aren't born, they're made,
Rich
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
This is a weighted average/mixture question.Tom is on a certain diet that requires him to limit the number of calories he takes in each day. He is allowed to take in 2400 calories each day from three square meals, and 200 calories each day from snacks and dessert combined. On some days, he splurges by taking in three times the recommended number of calories from snacks and dessert. The rest of the days, he follows the calorie guidelines precisely. If his average calorie intake for a 10 day period was 2720, on how many days did he splurge?
A. 3
B. 4
C. 5
D. 6
E. 7
Ingredient 1: Average caloric intake on deprived days = meal calories + snack calories = 2400 + 200 = 2600.
Ingredient 2: Average caloric intake on splurge days = meal calories + snack calories = 2400 + 3*200 = 3000.
Mixture: Average caloric intake for the MIXTURE of deprived days and splurge days = 2720.
Let D = the number of deprived days and S = the number of splurge days.
To determine the ratio of D to S in the mixture, use ALLIGATION:
Step 1: Plot the 3 averages on a number line, with the averages for the two ingredients on the ends and the average for the mixture in the middle.
D 2600--------------2720-------------3000 S
Step 2: Calculate the distances between the averages.
D 2600------120----2720-----280-----3000 S
Step 3: Determine the ratio in the mixture.
The required ratio of D to S is the RECIPROCAL of the distances in red.
D:S = 280:120 = 7:3.
Thus, of the 10 days, D=7 and S=3.
The correct answer is A.
For two similar problems, check here:
https://www.beatthegmat.com/ratios-fract ... 15365.html
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
GMATGuruNY wrote:This is a weighted average/mixture question.Tom is on a certain diet that requires him to limit the number of calories he takes in each day. He is allowed to take in 2400 calories each day from three square meals, and 200 calories each day from snacks and dessert combined. On some days, he splurges by taking in three times the recommended number of calories from snacks and dessert. The rest of the days, he follows the calorie guidelines precisely. If his average calorie intake for a 10 day period was 2720, on how many days did he splurge?
A. 3
B. 4
C. 5
D. 6
E. 7
Ingredient 1: Average caloric intake on deprived days = meal calories + snack calories = 2400 + 200 = 2600.
Ingredient 2: Average caloric intake on splurge days = meal calories + snack calories = 2400 + 3*200 = 3000.
Mixture: Average caloric intake for the MIXTURE of deprived days and splurge days = 2720.
Let D = the number of deprived days and S = the number of splurge days.
To determine the ratio of D to S in the mixture, use ALLIGATION:
Step 1: Plot the 3 averages on a number line, with the averages for the two ingredients on the ends and the average for the mixture in the middle.
D 2600--------------2720-------------3000 S
Step 2: Calculate the distances between the averages.
D 2600------120----2720-----280-----3000 S
Step 3: Determine the ratio in the mixture.
The required ratio of D to S is the RECIPROCAL of the distances in red.
D:S = 280:120 = 7:3.
Thus, of the 10 days, D=7 and S=3.
The correct answer is A.
For two similar problems, check here:
https://www.beatthegmat.com/ratios-fract ... 15365.html
That's an interesting approach. Thanks for the problem suggestion.
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
We can also apply the formula for weighted averages:aces021 wrote: ↑Sun Jun 08, 2014 9:55 amTom is on a certain diet that requires him to limit the number of calories he takes in each day. He is allowed to take in 2400 calories each day from three square meals, and 200 calories each day from snacks and dessert combined. On some days, he splurges by taking in three times the recommended number of calories from snacks and dessert. The rest of the days, he follows the calorie guidelines precisely. If his average calorie intake for a 10 day period was 2720, on how many days did he splurge?
A. 3
B. 4
C. 5
D. 6
E. 7
Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...
Given:
Regular days: 2600 calories
Splurge days: 3000 calories
Let R = number of days in which Tom ate the regular amount
Let S = number of days in which Tom splurged
Since there were 10 days altogether, we can write: R + S = 10
Next, from the above formula, we get: 2720 = (R/10)(2600) + (S/10)(3000)
Multiply both sides by 10 to get: 27200 = 2600R + 3000S
Divide both sides by 100 to get: 272 = 26R + 30S
Rewrite as: 26R + 30S = 272
We now have a system of two equations that we must solve for S:
R + S = 10
26R + 30S = 272
Take the top equation and multiply both sides by 26 to get:
26R + 26S = 260
26R + 30S = 272
Subtract the red equation from the blue equation to get: 4S = 12
Solve, S = 3
Answer: A