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Co-Ordinate Geometry

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kamalakarthi Senior | Next Rank: 100 Posts Default Avatar
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Co-Ordinate Geometry

Post Tue Aug 01, 2017 4:28 pm
Hi,

Can you help me with the below question.
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Post Mon Aug 07, 2017 3:40 pm
Hi kamalakarthi,

You can figure out the equation for the line by determining the Slope and then using the Slope-Intercept Formula. With that Formula, you can then determine every point on that line...

Two points that we know for certain are on the line are (4, 2) and (-2, -4). We can use those two points to find the Slope of the line:

(Change in Y)/(Change in X) = [2 - (-4)]/[4 - (-2)] = 6/6 = 1. With a slope of 1, we can now use the Slope-Intercept Formula:

Y = (M)(X) + B
Y = (1)(X) + B

Using either of the two co-ordinates that we started with, we can figure out the value of B...

(4, 2)
2 = (1)(4) + B
2 = 4 + B
-2 = B

Thus, the equation of the line is:
Y = X - 2

And we have proof that (2,0) is the co-ordinate that crosses the X-axis.

GMAT assassins aren't born, they're made,
Rich

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Post Fri Aug 18, 2017 1:09 pm
kamalakarthi wrote:
Thanks Matt. We know -2 is on the X-axis but how can we 2 is also on the X -axis. What if 1.8 is on the X-axis. This is the part I am having trouble with.

Can you help on what am I missing.
Sure! It can't be on the x-axis, since the lines will only intersect at one point, and we've already got an intersection between the two: x = 2 and y = 0 (the x-axis). Two straight lines can only intersect at one point - this is one of the cornerstones of Euclidean geometry. (Well, they can also intersect at zero points or all points, if they're parallel or identical!)

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Post Mon Aug 07, 2017 3:40 pm
Hi kamalakarthi,

You can figure out the equation for the line by determining the Slope and then using the Slope-Intercept Formula. With that Formula, you can then determine every point on that line...

Two points that we know for certain are on the line are (4, 2) and (-2, -4). We can use those two points to find the Slope of the line:

(Change in Y)/(Change in X) = [2 - (-4)]/[4 - (-2)] = 6/6 = 1. With a slope of 1, we can now use the Slope-Intercept Formula:

Y = (M)(X) + B
Y = (1)(X) + B

Using either of the two co-ordinates that we started with, we can figure out the value of B...

(4, 2)
2 = (1)(4) + B
2 = 4 + B
-2 = B

Thus, the equation of the line is:
Y = X - 2

And we have proof that (2,0) is the co-ordinate that crosses the X-axis.

GMAT assassins aren't born, they're made,
Rich

_________________
Contact Rich at Rich.C@empowergmat.com

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Matt@VeritasPrep GMAT Instructor
Joined
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2640 messages
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113 members
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625
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GMAT Score:
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Post Fri Aug 18, 2017 1:09 pm
kamalakarthi wrote:
Thanks Matt. We know -2 is on the X-axis but how can we 2 is also on the X -axis. What if 1.8 is on the X-axis. This is the part I am having trouble with.

Can you help on what am I missing.
Sure! It can't be on the x-axis, since the lines will only intersect at one point, and we've already got an intersection between the two: x = 2 and y = 0 (the x-axis). Two straight lines can only intersect at one point - this is one of the cornerstones of Euclidean geometry. (Well, they can also intersect at zero points or all points, if they're parallel or identical!)

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kamalakarthi Senior | Next Rank: 100 Posts Default Avatar
Joined
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Posted:
80 messages
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2 members
Post Mon Aug 07, 2017 8:16 am
Thanks Matt. We know -2 is on the X-axis but how can we 2 is also on the X -axis. What if 1.8 is on the X-axis. This is the part I am having trouble with.

Can you help on what am I missing.

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