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Co-Ordinate Geometry

This topic has 4 expert replies and 1 member reply
kamalakarthi Senior | Next Rank: 100 Posts Default Avatar
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Co-Ordinate Geometry

Post Tue Aug 01, 2017 4:28 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    Hi,

    Can you help me with the below question.
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    Post Tue Aug 01, 2017 8:45 pm
    Hi kamalakarthi,

    Based on the drawing - and the fact that the answer choices are relatively "spread out", you can answer this question 'visually.' We're looking for the X-coordinate values on the line in which Y < 0 (meaning that the Y-coordinate is below the X-axis). That certainly appears to occur somewhere between when X=0 and X=4. There's only one answer that logically matches....

    Mathematically, we can prove the correct answer. Two points that we know for certain are on the line are (4, 2) and (-2, -4). We can use those two points to find the Slope of the line:

    (Change in Y)/(Change in X) = [2 - (-4)]/[4 - (-2)] = 6/6 = 1. With a slope of 1, we can work "up" or "down" from either of those two co-ordinates. If you word "down" from (4,2), you would hit (3,1), (2,0), (1, -1), (0,-2), etc. Thus, when X < 2, we'll have a Y that is less than 0.

    Final Answer: D

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    Thanked by: kamalakarthi

    GMAT/MBA Expert

    Post Sun Aug 06, 2017 10:12 pm
    Another trick: notice where the line intercepts the x-axis, then work from there.

    We know (2, 0) is on the line and on the x-axis. We know that for all x-values < 2, the line is below the x-axis, and that for all x-values > 2, the line is above the x-axis.

    "Below the x-axis" is another way of saying y < 0, so for all x < 2, we'll have y-values on the line < 0.

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    kamalakarthi Senior | Next Rank: 100 Posts Default Avatar
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    Post Mon Aug 07, 2017 8:16 am
    Thanks Matt. We know -2 is on the X-axis but how can we 2 is also on the X -axis. What if 1.8 is on the X-axis. This is the part I am having trouble with.

    Can you help on what am I missing.

    Post Mon Aug 07, 2017 3:40 pm
    Hi kamalakarthi,

    You can figure out the equation for the line by determining the Slope and then using the Slope-Intercept Formula. With that Formula, you can then determine every point on that line...

    Two points that we know for certain are on the line are (4, 2) and (-2, -4). We can use those two points to find the Slope of the line:

    (Change in Y)/(Change in X) = [2 - (-4)]/[4 - (-2)] = 6/6 = 1. With a slope of 1, we can now use the Slope-Intercept Formula:

    Y = (M)(X) + B
    Y = (1)(X) + B

    Using either of the two co-ordinates that we started with, we can figure out the value of B...

    (4, 2)
    2 = (1)(4) + B
    2 = 4 + B
    -2 = B

    Thus, the equation of the line is:
    Y = X - 2

    And we have proof that (2,0) is the co-ordinate that crosses the X-axis.

    GMAT assassins aren't born, they're made,
    Rich

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    Post Fri Aug 18, 2017 1:09 pm
    kamalakarthi wrote:
    Thanks Matt. We know -2 is on the X-axis but how can we 2 is also on the X -axis. What if 1.8 is on the X-axis. This is the part I am having trouble with.

    Can you help on what am I missing.
    Sure! It can't be on the x-axis, since the lines will only intersect at one point, and we've already got an intersection between the two: x = 2 and y = 0 (the x-axis). Two straight lines can only intersect at one point - this is one of the cornerstones of Euclidean geometry. (Well, they can also intersect at zero points or all points, if they're parallel or identical!)

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