A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?
(1) If two more women were available for selection, exactly 56 different groups of three women could be selected.
(2) x = y + 1
OA is C
Choosing women from a Panel
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(1) (w+2)C2 * yC2 = 56umaa wrote:A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?
(1) If two more women were available for selection, exactly 56 different groups of three women could be selected.
(2) x = y + 1
OA is C
(w+2)(w+1)/2! * y(y -1)/2! = 56
INSUFFICIENT
(2) INSUFFICIENT
(1) + (2) SUFFICIENT
i think stmt 1 you have wrongly formulated...aj5105 wrote:(1) (w+2)C2 * yC2 = 56umaa wrote:A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?
(1) If two more women were available for selection, exactly 56 different groups of three women could be selected.
(2) x = y + 1
OA is C
(w+2)(w+1)/2! * y(y -1)/2! = 56
INSUFFICIENT
(2) INSUFFICIENT
(1) + (2) SUFFICIENT
we need to find xC3*yC2......
now as per stmt1,
if 2 more women were there then total women x+2
so the no. of ways selecting three women is (x+2)C3 and given that (x+2)C3=56
so x is known but still y not known. hence not sufficient.
but stmt 2 alone is also not sufficient because x& y both r unknown.
but if you use both stmt,
u may find x from first stmt first
and then y from second stmt.
hence C as xC3*yC2 can be calculated now.
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The answer is C for sure, but I don't think the question can be correct...
There is no such value for x such that nCr(x, 3) = 56, so A doesn't make sense.
There is no such value for x such that nCr(x, 3) = 56, so A doesn't make sense.
Have you wondered how you could have found such a treasure? -T
no buddy! 8C3 surely makes 56. so there is a value of x available...Domnu wrote:The answer is C for sure, but I don't think the question can be correct...
There is no such value for x such that nCr(x, 3) = 56, so A doesn't make sense.