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Stuart Kovinsky GMAT Instructor
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Post Tue May 01, 2012 10:54 am
Hi!

You seem to have misinterpreted the question as "what is the smallest possible number in the set?", when in fact it's simply "what is the smallest number in the set?"

With (1) alone, there's no way to determine the actual value of x, y or z, so (1) is insufficient.

Stuart

shantanu86 wrote:
Night reader wrote:
If the range of the set containing the numbers x, y, and z is 8, what is the value of the smallest number in the set?

(1) The average of the set containing the numbers x, y, z, and 8 is 12.5.
(2) The mean and the median of the set containing the numbers x, y, and z are equal.
This is a great question.. But contrary to popular opinion here, I think the answer is [A]
Lets analyze..

(1) (x+y+z+8) = 4*12.5
=> average of x,y and z is 14

So one of the solution set which satisfies (1) is
(18,14,10)
Now to minimize the smallest number I decrease minimum and balance other two for mean to be 14

(17,16,9).. integral solution with 9 as smallest

(16.66,16.66, 8.66) .. non-integral solution with 8.66 as smallest

Hence (1) alone is sufficient and obviously (2) alone is not sufficient.
Therefore the correct answer is [A].

Hope it helps!!

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miteshpant Just gettin' started!
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Post Thu Jul 19, 2012 12:28 am
Hi,

No where its said that the numbers are integers. So i think it must be E

optimist Just gettin' started! Default Avatar
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Post Fri Jul 20, 2012 11:34 am
miteshpant wrote:
Hi,

No where its said that the numbers are integers. So i think it must be E
Here, when you combine stmt 1 and stmt 2, you get:
x+y+z=42
assuming 'y' as the median, we get
x+z=42-14=28 ---1
and we know, x-z = 8 ---2

solving 1 and 2 we get x=18 and z=10

So, I don't think there is any question of the numbers being non integers..

Pls let me know if I have missed anything here

Thanks

ashg84 Rising GMAT Star Default Avatar
Joined
09 Jul 2011
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48 messages
Post Tue Oct 16, 2012 2:16 am
Hi,

I agree with you.. The question is not asking for smallest possible but the smallest number in the set. Two things are entirely different. In my views the answer should be E as we can not find the smallest number with these two statement. Please suggest if my interpretation of the question is wrong.

What is the OA.

Thanks

Ashish Gupta \

Stuart Kovinsky wrote:
Hi!

You seem to have misinterpreted the question as "what is the smallest possible number in the set?", when in fact it's simply "what is the smallest number in the set?"

With (1) alone, there's no way to determine the actual value of x, y or z, so (1) is insufficient.

Stuart

shantanu86 wrote:
Night reader wrote:
If the range of the set containing the numbers x, y, and z is 8, what is the value of the smallest number in the set?

(1) The average of the set containing the numbers x, y, z, and 8 is 12.5.
(2) The mean and the median of the set containing the numbers x, y, and z are equal.
This is a great question.. But contrary to popular opinion here, I think the answer is [A]
Lets analyze..

(1) (x+y+z+8) = 4*12.5
=> average of x,y and z is 14

So one of the solution set which satisfies (1) is
(18,14,10)
Now to minimize the smallest number I decrease minimum and balance other two for mean to be 14

(17,16,9).. integral solution with 9 as smallest

(16.66,16.66, 8.66) .. non-integral solution with 8.66 as smallest

Hence (1) alone is sufficient and obviously (2) alone is not sufficient.
Therefore the correct answer is [A].

Hope it helps!!

ashg84 Rising GMAT Star Default Avatar
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Posted:
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Post Tue Oct 16, 2012 2:23 am
My mistake, answer should be C.

rajeshsinghgmat Really wants to Beat The GMAT! Default Avatar
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Post Wed Feb 20, 2013 2:45 am
C in answer.

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