(1) when n is divided by 110, the remainder is 75.
(2) When n is divided by 100, the remainder is 25.
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Can You solve this "remainder" question?
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EbrahimHashem
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What is the remainder when integer n is dvided by 10?
(1) when n is divided by 110, the remainder is 75.
(2) When n is divided by 100, the remainder is 25.
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(1) when n is divided by 110, the remainder is 75.
(2) When n is divided by 100, the remainder is 25.
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cramya
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D
Stmt I
n = 110q+75
110 always divisble by 10 so the remiander will be what 75 will leave when divided by 10 i.e 5
SUFF
Stmt II
n = 100q+25
100 always divisble by 10 so the remiander will be what 25 will leave when divided by 10 i.e 5
SUFF
Only prob is the 2 statements here contradict each other i.e. if we take n=75 then it does not leave a remainder 25 when divided by 100. In gmat q's this will not be the case
Stmt I
n = 110q+75
110 always divisble by 10 so the remiander will be what 75 will leave when divided by 10 i.e 5
SUFF
Stmt II
n = 100q+25
100 always divisble by 10 so the remiander will be what 25 will leave when divided by 10 i.e 5
SUFF
Only prob is the 2 statements here contradict each other i.e. if we take n=75 then it does not leave a remainder 25 when divided by 100. In gmat q's this will not be the case
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Ian Stewart
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Yes, n can't be 75, but the statements aren't contradictory - n could be 625, 1725, 2825, etc.cramya wrote: Only prob is the 2 statements here contradict each other i.e. if we take n=75 then it does not leave a remainder 25 when divided by 100. In gmat q's this will not be the case
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cubicle_bound_misfit
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Basically,
the question is asking ...what is the unit digit of n
Using both statements independently,
each time unit digit is 5 (use VIC method)
hence D.
the question is asking ...what is the unit digit of n
Using both statements independently,
each time unit digit is 5 (use VIC method)
hence D.
Cubicle Bound Misfit
