at a baseball game each player on the red team hits 2/3 as many balls each player on the blue team did. if the red team has 5/6 as many players as the blue team the approximately what percent al all the balls hit at the game were hit by the blue team?
A.25 %
B.56%
C.64%
D.66(2/3)%
baseball problem
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Let the number of players in blue team = B
Let the balls hit by a player on blue team be = x
Balls hit by the blue team = Bx
Balls hit by read team = 5/6 * B * 2/3 * x= 5/9 * Bx
Total balls hit = Bx + (5/9 * Bx) = 14/9 Bx
% of balls hit by blue team = [Bx / (14/9 Bx) ] * 100 = 900/14 ~= 64 %
IMO Answer is C
Let the balls hit by a player on blue team be = x
Balls hit by the blue team = Bx
Balls hit by read team = 5/6 * B * 2/3 * x= 5/9 * Bx
Total balls hit = Bx + (5/9 * Bx) = 14/9 Bx
% of balls hit by blue team = [Bx / (14/9 Bx) ] * 100 = 900/14 ~= 64 %
IMO Answer is C