If x and y are consecutive negative integers, is x greater than y?
x + 1 and y - 1 are consecutive negative integers.
x is an even integer
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DS - Consecutive negative integers
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karthikpandian19
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Anurag@Gurome
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Statement 1: Note that the following pairs are consecutive negative integers,karthikpandian19 wrote:If x and y are consecutive negative integers, is x greater than y?
x + 1 and y - 1 are consecutive negative integers.
x is an even integer
- x and y
x and (x + 1)
y and (y - 1)
(x + 1) and (y - 1)
Therefore, x < y
Sufficient
Statement 2: This is not enough to draw any relevant conclusion. For example,
- 1. x = -2 and y -1 --> x < y
2. x = -2 and y = -2 --> x = y
3. x = -2 and y = -3 --> x > y
The correct answer is A.
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karthikpandian19
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OA is A
Regards,
Karthik
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GMATGuruNY
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The different between consecutive integers is 1.karthikpandian19 wrote:If x and y are consecutive negative integers, is x greater than y?
x + 1 and y - 1 are consecutive negative integers.
x is an even integer
Statement 1: x+1 and y-1 are consecutive negative integers.
Case 1:
(x+1) - (y-1) = 1.
1 = y-x.
This works: the difference between y and x is 1, satisfying the condition that x and y are consecutive integers.
In this case, y>x.
Case 2:
(y-1) - (x+1) = 1
y-x = 3.
Doesn't work: x and y are not consecutive integers.
Since only Case 1 is possible, y>x.
SUFFICIENT.
Statement 2: x is even.
No information about y.
INSUFFICIENT.
The correct answer is A.
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karthikpandian19
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I am pretty confused with ur explanation on Statement 1 - Case 2.........
Suppose, if -9 & -10 are two consec. intg;
(-9) - (-10) = 1 true
(-10) - (-9) = -1 false but the magnitude / value should be same
But how come it comes to 3, in your explanation???
Suppose, if -9 & -10 are two consec. intg;
(-9) - (-10) = 1 true
(-10) - (-9) = -1 false but the magnitude / value should be same
But how come it comes to 3, in your explanation???
GMATGuruNY wrote:The different between consecutive integers is 1.karthikpandian19 wrote:If x and y are consecutive negative integers, is x greater than y?
x + 1 and y - 1 are consecutive negative integers.
x is an even integer
Statement 1: x+1 and y-1 are consecutive negative integers.
Case 1:
(x+1) - (y-1) = 1.
1 = y-x.
This works: the difference between y and x is 1, satisfying the condition that x and y are consecutive integers.
In this case, y>x.
Case 2:
(y-1) - (x+1) = 1
y-x = 3.
Doesn't work: x and y are not consecutive integers.
Since only Case 1 is possible, y>x.
SUFFICIENT.
Statement 2: x is even.
No information about y.
INSUFFICIENT.
The correct answer is A.
Regards,
Karthik
The source of the questions that i post from JUNE 2013 is from KNEWTON
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Karthik
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GMATGuruNY
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Statement 1 tells us that (x+1) and (y-1) are consecutive integers.karthikpandian19 wrote:I am pretty confused with ur explanation on Statement 1 - Case 2.........
Suppose, if -9 & -10 are two consec. intg;
(-9) - (-10) = 1 true
(-10) - (-9) = -1 false but the magnitude / value should be same
But how come it comes to 3, in your explanation???
Thus, there are two possibilities:
Case 1: (x+1) is one more than (y-1).
Case 2: (y-1) is one more than (x+1).
Case 2 implies the following:
(y-1) - (x+1) = 1.
y-x = 3.
Here, x and y are not consecutive integers.
Since the question stem REQUIRES that x and y be consecutive integers, Case 2 is not viable.
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As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
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