There is a set of 160 numbers, beginning at 6, with each subsequent term increasing
by an increment of 3. What is the average of this set of numbers?
I am not able to understand how to calculate the last digit?to calculate the average.
Average | Manhattan strategy guides
This topic has expert replies
- [email protected]
- Master | Next Rank: 500 Posts
- Posts: 206
- Joined: Sun Jun 24, 2012 5:44 pm
- Thanked: 5 times
- Followed by:3 members
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
[email protected] wrote:There is a set of 160 numbers, beginning at 6, with each subsequent term increasing
by an increment of 3. What is the average of this set of numbers?
I am not able to understand how to calculate the last digit?to calculate the average.
There's an important rule that says, "If the numbers in a set are equally spaced, then the mean and median of that set are equal"
So, for example, the mean and median of this set {1, 4, 7, 10, 13, 16} are equal since the numbers are evenly/equally spaced.
In this question, we have 160 numbers. They look like this: {6, 9, 12, 15, . . . }
We can find either the mean or the median, since they'll be equal here.
Let's find the median.
Since there's an even number of integers in the set, we'll need to find the mean of the two middle numbers. In other words, we'll need to find the mean of the 80th value and the 81st value in the set.
But what are the 80th and 81st values in the set?
To find out, let's rewrite the numbers in the set {6, 9, 12, 15, ..}
1st value = 6 = 3 + 3
2nd value = 9 = 3 + 2(3)
3rd value = 12 = 3 + 3(3)
4th value = 15 = 3 + 4(3)
5th value = 18 = 3 + 5(3)
.
.
.
From this we can see a pattern.
80th value = 3 + 80(3) = 243
81st value = 3 + 81(3) = 246
The median (aka the mean) of all 160 terms will equal the mean of 243 and 246.
Median = (243 + 246)/2 = 244.5
So the mean and median are both 244.5
Cheers,
Brent
Last edited by Brent@GMATPrepNow on Mon Oct 01, 2012 8:36 pm, edited 1 time in total.
-
- Master | Next Rank: 500 Posts
- Posts: 392
- Joined: Thu Jan 15, 2009 12:52 pm
- Location: New Jersey
- Thanked: 76 times
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
Nice catch - I've corrected it.truplayer256 wrote:Great Job by Brent up there! Just one correction, I think it should be 244.5 and not 245.5.
Cheers,
Brent
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
The above rule can save you a lot of time on some GMAT questions.Brent@GMATPrepNow wrote: If the numbers in a set are equally spaced, then the mean and median of that set are equal
Here's an article on the topic: https://www.beatthegmat.com/mba/2012/05/ ... d-the-mean
And here are 4 related practice questions:
- https://www.beatthegmat.com/og-question- ... 16004.html
- https://www.beatthegmat.com/set-nds-t82611.html
- https://www.beatthegmat.com/og-question- ... 16004.html
- https://www.beatthegmat.com/0-is-added-t ... 92300.html
Cheers,
Brent
- gmat6087
- Senior | Next Rank: 100 Posts
- Posts: 53
- Joined: Sat Oct 29, 2011 3:49 am
- Thanked: 2 times
- Followed by:1 members
Brent@GMATPrepNow wrote:[email protected] wrote:There is a set of 160 numbers, beginning at 6, with each subsequent term increasing
by an increment of 3. What is the average of this set of numbers?
I am not able to understand how to calculate the last digit?to calculate the average.
There's an important rule that says, "If the numbers in a set are equally spaced, then the mean and median of that set are equal"
So, for example, the mean and median of this set {1, 4, 7, 10, 13, 16} are equal since the numbers are evenly/equally spaced.
In this question, we have 160 numbers. They look like this: {6, 9, 12, 15, . . . }
We can find either the mean or the median, since they'll be equal here.
Let's find the median.
Since there's an even number of integers in the set, we'll need to find the mean of the two middle numbers. In other words, we'll need to find the mean of the 80th value and the 81st value in the set.
But what are the 80th and 81st values in the set?
To find out, let's rewrite the numbers in the set {6, 9, 12, 15, ..}
1st value = 6 = 3 + 3
2nd value = 9 = 3 + 2(3)
3rd value = 12 = 3 + 3(3)
4th value = 15 = 3 + 4(3)
5th value = 18 = 3 + 5(3)
.
.
.
From this we can see a pattern.
80th value = 3 + 80(3) = 243
81st value = 3 + 81(3) = 246
The median (aka the mean) of all 160 terms will equal the mean of 243 and 246.
Median = (243 + 246)/2 = 244.5
So the mean and median are both 244.5
Cheers,
Brent
Hi Brent,
I may sound silly, but I just need a clarification. The question says the number begins with 6 and subsequent number is incremented by 3.
So the pattern I assume Should be:
1st value = 6 = 6 + 0
2nd value = 9 = 6 + 1(3)
3rd value = 12 = 6 + 2(3)
4th value = 15 = 6 + 3(3)
5th value = 18 = 6 + 4(3)
.
.
.
From this we can see a pattern.
80th value = 6 + 80(3) = 246
81st value = 6 + 81(3) = 249
Please correct me if I an wrong.
-
- Master | Next Rank: 500 Posts
- Posts: 118
- Joined: Mon May 21, 2012 10:07 pm
- Thanked: 23 times
- Followed by:4 members
Hi nishat
Another approach:
The given series is an AP with
(1st term) a = 6,
(no of terms) n = 160,
(common diff) d = 3
(last term) l = a+(n-1)d = 6+(159)3 = 483
Avg = (a+l)/2 = (6+483)/2 = 244.5
Hope it helps![Smile :)](./images/smilies/smile.png)
Another approach:
The given series is an AP with
(1st term) a = 6,
(no of terms) n = 160,
(common diff) d = 3
(last term) l = a+(n-1)d = 6+(159)3 = 483
Avg = (a+l)/2 = (6+483)/2 = 244.5
Hope it helps
![Smile :)](./images/smilies/smile.png)
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
Your way works perfectly fine as well.gmat6087 wrote: Hi Brent,
I may sound silly, but I just need a clarification. The question says the number begins with 6 and subsequent number is incremented by 3.
So the pattern I assume Should be:
1st value = 6 = 6 + 0
2nd value = 9 = 6 + 1(3)
3rd value = 12 = 6 + 2(3)
4th value = 15 = 6 + 3(3)
5th value = 18 = 6 + 4(3)
.
.
.
From this we can see a pattern.
80th value = 6 + 80(3) = 246
81st value = 6 + 81(3) = 249
Please correct me if I an wrong.
In my approach, I arranged it so that the numbers match up.
For example, 5th value = 18 = 3 + 5(3) . . . and 80th value = 3 + 80(3) = 243
In your approach, we need to be careful and recognize that the numbers don't match up. That is they are 1 off. Example: 5th value = 18 = 6 + 4(3).
So, continuing along . . . 80th value = 6 + 79(3) = 243
(you have 80th value = 6 + 80(3) = 246) . . . and 81st value = 6 + 80[/blue](3) = 246
Cheers,
Brent
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
Your way works perfectly fine as well.gmat6087 wrote: Hi Brent,
I may sound silly, but I just need a clarification. The question says the number begins with 6 and subsequent number is incremented by 3.
So the pattern I assume Should be:
1st value = 6 = 6 + 0
2nd value = 9 = 6 + 1(3)
3rd value = 12 = 6 + 2(3)
4th value = 15 = 6 + 3(3)
5th value = 18 = 6 + 4(3)
.
.
.
From this we can see a pattern.
80th value = 6 + 80(3) = 246
81st value = 6 + 81(3) = 249
Please correct me if I an wrong.
In my approach, I arranged it so that the numbers match up.
For example, 5th value = 18 = 3 + 5(3) . . . and 80th value = 3 + 80(3) = 243
In your approach, we need to be careful and recognize that the numbers don't match up. That is they are 1 off. Example: 5th value = 18 = 6 + 4(3).
So, continuing along . . . 80th value = 6 + 79(3) = 243
(you have 80th value = 6 + 80(3) = 246) . . . and 81st value = 6 + 80(3) = 246
Cheers,
Brent
- LalaB
- Master | Next Rank: 500 Posts
- Posts: 425
- Joined: Wed Dec 08, 2010 9:00 am
- Thanked: 56 times
- Followed by:7 members
- GMAT Score:690
one more solution-
average= (last term+first term)/2=(A160th+A1)/2
note that we have the following set-
6 9 12 15 etc
it means we have multiple of 3 plus 3 . a1=1*3+3=6 a2=2*3+3=9 etc
so, A160=160*3+3=483
(483+6)/2=244.5
average= (last term+first term)/2=(A160th+A1)/2
note that we have the following set-
6 9 12 15 etc
it means we have multiple of 3 plus 3 . a1=1*3+3=6 a2=2*3+3=9 etc
so, A160=160*3+3=483
(483+6)/2=244.5
Happy are those who dream dreams and are ready to pay the price to make them come true.(c)
In order to succeed, your desire for success should be greater than your fear of failure.(c)
In order to succeed, your desire for success should be greater than your fear of failure.(c)