issen is trying to select an assistant from a pool A application,if 1/5 of them really want to be actors,and of those 2/3 really want to be directors, then in terms of A, how many of the applicants dont want to be both actors and directors?
A. 2A/15
b.A/5
C.A/3
D.7A/8
E.13A/15
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assitant problem
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pradeepkaushal9518
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Last edited by pradeepkaushal9518 on Wed May 19, 2010 6:04 am, edited 1 time in total.
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liferocks
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it should be A{1-(1/5+2/3)}=2A/15 if we assume no one wants to be both actor as well as director
Not sure whether we can assume this.If we can Ans is option A
Not sure whether we can assume this.If we can Ans is option A
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pradeepkaushal9518
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asamaverick
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pradeepkaushal9518 wrote:issen is trying to select an assistant from a pool A application,if 1/5 of them really want to be actors,and of those 2/3 really want to be directors, then in terms of A, how many of the applicants dont want to be both actors and directors?
A. 2A/15
b.A/5
C.A/3
D.7A/8
E.13A/15
A/5 want to be actors. Of these 2/3 want to be directors = A/5 * 2/3 = 2A/15.
The way I interpret it, 2A/15 want to be both actor and director. So the number of people who do not want to be both actor & director = A - 2A/15 = 13A/15.
So IMO it's E.
I agree with asamavrick.
Here are my steps:
first found the LCM of 3 and 5 = 15 = A
(1/5)*15 = 3 = # who want to be actors
(2/3)*3 = 2 want to be be both actors and directors
Number of applicants who don't want to be both = 15 - 2 = 13
plug 15 for A you get E
Here are my steps:
first found the LCM of 3 and 5 = 15 = A
(1/5)*15 = 3 = # who want to be actors
(2/3)*3 = 2 want to be be both actors and directors
Number of applicants who don't want to be both = 15 - 2 = 13
plug 15 for A you get E
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pradeepkaushal9518
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