area of triangle
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Hi,
If a,b,c are the sides of the triangle then area of triangle is given by (1/2)*b*c*sine A
So, Area = (1/2)*(12)*(8)*sine A = 48 sine A
As 0<sine A<=1, area will be less than or equal to 48 and equality holds when the angle between these two sides is 90 degrees.
Hence, B
If you are not comfortable with sines, you can follow illustrations by experts at:
https://www.beatthegmat.com/area-when-si ... 86637.html
If a,b,c are the sides of the triangle then area of triangle is given by (1/2)*b*c*sine A
So, Area = (1/2)*(12)*(8)*sine A = 48 sine A
As 0<sine A<=1, area will be less than or equal to 48 and equality holds when the angle between these two sides is 90 degrees.
Hence, B
If you are not comfortable with sines, you can follow illustrations by experts at:
https://www.beatthegmat.com/area-when-si ... 86637.html
Cheers!
Things are not what they appear to be... nor are they otherwise
Things are not what they appear to be... nor are they otherwise