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Another Exponent / Remainder Question
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chetanojha
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bharathh
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Remainder is always 4
Just consider the units digit for this question. Rest is not required.
2^8 = 256
256^x will always have units digit 6... 6 + 2 will make the units digit 8
Add 6 to that... and units digit will be 4
When a number having a units digit of 4 is divided by 5 remainder will always be 4
Just consider the units digit for this question. Rest is not required.
2^8 = 256
256^x will always have units digit 6... 6 + 2 will make the units digit 8
Add 6 to that... and units digit will be 4
When a number having a units digit of 4 is divided by 5 remainder will always be 4
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vittalgmat
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This is a relatively old problem that I came across.
I always get the remainder as 0.
Pls let me know if I am missing something.
eg. if x = 1
then the expr becomes 2^10 ==> 1024 ==> units digit is 4
Add 6 to this. The unit digit becomes 0 which is always divisible by 5.
I always get the remainder as 0.
Pls let me know if I am missing something.
eg. if x = 1
then the expr becomes 2^10 ==> 1024 ==> units digit is 4
Add 6 to this. The unit digit becomes 0 which is always divisible by 5.
