What is the value of (x^6+x^-6) ?
1) x^6 - x^-6 = 128
2) x^3 + x^-3 = 14
Algebra
This topic has expert replies
-
- Legendary Member
- Posts: 966
- Joined: Sat Jan 02, 2010 8:06 am
- Thanked: 230 times
- Followed by:21 members
- knight247
- Legendary Member
- Posts: 504
- Joined: Tue Apr 19, 2011 1:40 pm
- Thanked: 114 times
- Followed by:11 members
Let x³=a and 1/x³=b so a²=x^6 and b²=1/(x^6)
we need to find the value of a²+b²
1)a²-b²=128
(a-b)(a+b)=128 no way to solve further so INSUFFICIENT
2)a+b=14
Now way to solve further.
Combining both. Put a+b=14 in (a-b)(a+b)=128 we get (a-b)*14=128 so a-b=some value Solve this simultaneously with a+b=14. U'll get some value of a and b so you'll have the value of x^3 and 1/x^. Next find the value of x^6 and 1/x^6. Hence C
we need to find the value of a²+b²
1)a²-b²=128
(a-b)(a+b)=128 no way to solve further so INSUFFICIENT
2)a+b=14
Now way to solve further.
Combining both. Put a+b=14 in (a-b)(a+b)=128 we get (a-b)*14=128 so a-b=some value Solve this simultaneously with a+b=14. U'll get some value of a and b so you'll have the value of x^3 and 1/x^. Next find the value of x^6 and 1/x^6. Hence C
-
- Senior | Next Rank: 100 Posts
- Posts: 40
- Joined: Mon Oct 18, 2010 8:32 am
2 => x^3 + x^-3 = 14shankar.ashwin wrote:What is the value of (x^6+x^-6) ?
1) x^6 - x^-6 = 128
2) x^3 + x^-3 = 14
squaring on both sides
=> (x^3)^2 + (x^-3)^2 + 2(x^3)(x^-3) = 196
=> x^6 + x^-6 = 194
So B is sufficient
-
- Legendary Member
- Posts: 966
- Joined: Sat Jan 02, 2010 8:06 am
- Thanked: 230 times
- Followed by:21 members
The OA is D
shankar.ashwin wrote:What is the value of (x^6+x^-6) ?
1) x^6 - x^-6 = 128
2) x^3 + x^-3 = 14