Is a + b > 0?
1. 7a - b > 0
2. b - 6a > 0
[spoiler]How C is the answer ?[/spoiler]
Algebra
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Statement 1:heshamelaziry wrote:Is a + b > 0?
1. 7a - b > 0
2. b - 6a > 0
[spoiler]How C is the answer ?[/spoiler]
7a - b > 0
7a > b
So, 7 a's are bigger than 1 b, but we don't know their positive/negative status. Insufficient.
Statement 2: Similar reasoning. Insufficient.
Combo:
When the inequality arrows are pointing in the same direction, you can stack the inequalities, and add them:
7a - b > 0
b - 6a > 0;
...rearranging
7a - b > 0
-6a +b > 0
_____________
a > 0 (adding the two inequalities)
So, a is positive. The second statement tells us:
b > 6a
If a is pos, and b is bigger than "a" (bigger than six of them), then of course, b is also positive.
Because both a and b are positive, their sum is positive.
The statements, although independently insufficient, are sufficient in combination.
Choose C.
Kaplan Teacher in Toronto
Look at statement 1 first
7a-b>0
First do two easy plugs
senario 1. a=2 and b=3 7(2)-3>0 and 2+3>0
snenario 2. a=-2 and b=-20 (7(-2))- (-20)>0 and -2 + (-20) = -22 <0
so does not answer the question
2. b-6a>0
use same plugs
Senario 1. b=10 and a=1 10-6(1)>0 10+1>0
Senario 2. b=-2 and a=2 -2-(6(-2))>0 2+ (-2) =0
So does not answer the question
Now if we use both together we can answer the question
7a-b>0
First do two easy plugs
senario 1. a=2 and b=3 7(2)-3>0 and 2+3>0
snenario 2. a=-2 and b=-20 (7(-2))- (-20)>0 and -2 + (-20) = -22 <0
so does not answer the question
2. b-6a>0
use same plugs
Senario 1. b=10 and a=1 10-6(1)>0 10+1>0
Senario 2. b=-2 and a=2 -2-(6(-2))>0 2+ (-2) =0
So does not answer the question
Now if we use both together we can answer the question