At 8am on Thursday, two workers, A and B, each start working

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At 8 am on Thursday, two workers, A and B, each start working independently to build identical decorative lamps. Worker A completes her lamp at 5 pm on Friday, while Worker B completes her lamp sometime during the morning on Friday. If both workers adhere to working hours of 8 am to 12 pm and 1 pm to 5 pm each day, at which of the following times might the two workers have completed a single lamp had they worked together at their respective constant rates?

A. Thursday, 1:30 pm
B. Thursday, 2:15 pm
C. Thursday, 3:00 pm
D. Thursday, 4:15 pm
E. Friday, 12:00 pm

The OA is C.

Please, can anyone explain this PS question for me? I can't get the correct answer. I need help to solve it. Thanks.

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A and B

by GMATGuruNY » Wed May 23, 2018 11:51 am
swerve wrote:At 8 am on Thursday, two workers, A and B, each start working independently to build identical decorative lamps. Worker A completes her lamp at 5 pm on Friday, while Worker B completes her lamp sometime during the morning on Friday. If both workers adhere to working hours of 8 am to 12 pm and 1 pm to 5 pm each day, at which of the following times might the two workers have completed a single lamp had they worked together at their respective constant rates?

A. Thursday, 1:30 pm
B. Thursday, 2:15 pm
C. Thursday, 3:00 pm
D. Thursday, 4:15 pm
E. Friday, 12:00 pm
Worker A takes two 8-hour days to produce a lamp, for a total of 16 hours.
Since Worker B finishes sometime Friday morning, B takes between 8 and 12 hours to produce a lamp.

Let each lamp = 48 units.
A's rate = w/t = 48/16 = 3 unit per hour.
If B takes 8 hours to produce a lamp, B's rate = w/t = 48/8 = 6 units per hour.
If B takes 12 hours to produce a lamp. B's rate = w/t = 48/12 = 4 units per hour.
Thus, B's rate must be BETWEEN 4 units per hour and 6 units per hour, implying that the combined rate for A and B must be between 3+4=7 units per hour and 3+6=9 units per hour.

If A and B work at 7 units per hour, the time produce a 48-unit lamp = 48/7 ≈ 7 hours.
If A and B work at 9 units per hour, the time produce a 48-unit lamp = 48/9 = 5.33 hours.
Since the rate for A and B together must be between 7 units per hour and 9 units per hour, the time for them to produce one 48-unit lamp must be MORE THAN 5.33 HOURS but LESS THAN 7 HOURS.
5.33 hours = (8am to 12pm) + (1pm to 2:15pm).
7 hours = (8am to 12pm) + (1pm to 4pm).
The times in blue imply that the lamp will be completed sometime between 2:15pm and 4pm.

The correct answer is C.
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hi

by Scott@TargetTestPrep » Thu May 24, 2018 4:59 pm
swerve wrote:At 8 am on Thursday, two workers, A and B, each start working independently to build identical decorative lamps. Worker A completes her lamp at 5 pm on Friday, while Worker B completes her lamp sometime during the morning on Friday. If both workers adhere to working hours of 8 am to 12 pm and 1 pm to 5 pm each day, at which of the following times might the two workers have completed a single lamp had they worked together at their respective constant rates?

A. Thursday, 1:30 pm
B. Thursday, 2:15 pm
C. Thursday, 3:00 pm
D. Thursday, 4:15 pm
E. Friday, 12:00 pm
We see that a workday is 8 hours (4 hours in the morning and 4 hours in the afternoon). Thus, it takes 2 workdays, or 16 hours, for worker A to complete her lamp, and therefore, her rate is 1/16. We are given that worker B completes her lamp sometime during the morning on Friday. Thus, it takes her more than 1 workday (or 8 hours) and less than 1 ½ workday (or 12 hours) to complete her lamp, and therefore, her rate is greater than 1/12 but less than 1/8. These two rates are the lower and upper bounds of worker B's rate, respectively.

At the upper bound of worker B's rate, if the two workers work together, it will take 1/(1/16 + 1/8) = 1/(1/16 + 2/16) = 1/(3/16) = 16/3 = 5 1/3 hr = 5 hr 20 min to complete one single lamp. Therefore, they will finish by 2:20 pm on Thursday (4 hours from 8 am to 12 pm and 1 hr 20 min after 1 pm).

At the lower bound of worker B's rate, if the two workers work together, it will take 1/(1/16 + 1/12) = 1/(3/48 + 4/48) = 1/(7/48) = 48/7 = 6 6/7 hr ≈ 6 hr 51 min to complete one single lamp. Therefore, they will finish by 3:51 pm on Thursday (4 hours from 8 am to 12 pm and 2 hr 51 min after 1 pm).

Since worker B's rate is between 1/12 and 1/8, the time when they work together will between 2:20 pm and 3:51 pm on Thursday. The only time in the given answer choices is choice C: Thursday, 3:00 pm. Thus choice C is the correct answer.

Answer: C

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