Is ax>bx?
(1)a>b
(2)a+x>b+x
Don't have an OA. Detailed explanations would be appreciated.
Inequality again
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- kmittal82
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Is ax > bx
Or, rephrasing
Is x(a-b) > 0
This true under 2 conditions:
x>0 AND a>b
OR
x<0 AND a<b
In either case, we need both the value of x and the relationship between a and b to determine the answer to the inequality
(1)
Tells us a>b, but nothing about x, not sufficient
(2)
Same as (1), i.e. a>b
Combining (1) and (2) is pointless, since both give the same result
Hence, I think its (E)
Or, rephrasing
Is x(a-b) > 0
This true under 2 conditions:
x>0 AND a>b
OR
x<0 AND a<b
In either case, we need both the value of x and the relationship between a and b to determine the answer to the inequality
(1)
Tells us a>b, but nothing about x, not sufficient
(2)
Same as (1), i.e. a>b
Combining (1) and (2) is pointless, since both give the same result
Hence, I think its (E)
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Required: ax>bx?knight247 wrote:Is ax>bx?
(1)a>b
(2)a+x>b+x
Don't have an OA. Detailed explanations would be appreciated.
= ax-bx>0
= x(a-b)>0
The above inequality is valid under the following conditions: When X>0 and a-b>0, which implies a>b, or when x<o and a-b<0. So the question is basically to see whether the statements satisfy any of these conditions.
Statement 1: only a>b, without giving any idea about X. So Insufficient.
Statement 2: a+x>b+x = a+x-b-x>0 =a-b>0 = a>b. This statement gives a different version of the first statement. Hence Insufficient.
Both: No additional info., as both statements are equivalent.
Hence, the answer is E.