Hi There. I'm a new user who is getting crazy with a few questions. Please find them below:
1. In how many different ways can 3 girls and 3 boys be seated at a rectangular table that has 3 chairs on one side and 3 stools on the other side, if two girls or two boys can never sit side by side.
2. Is 1>1/x?
(1)1>x
(2)x>0
3. When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land on the same side each time?
4. A worker is hired for five days. He is paid $5.00 more for each day of work than he was paid for the preceding day of work. What was the total amount he was paid for the five days of work?
(1) He had made 50% of the total by the end of the third day.
(2) He was paid twice as much for the last day as he was for the first day.
King Regards.
4 questions on Quantitative
This topic has expert replies
This is my take on these problems IMHO
(1) The arrangement is of the form
G B G
______
| |
______
B G B
So the guys can sit in 3! ways and the girls can sit in 3! ways and hence total num of ways = 3!*3! i.e. 36
(I am not 100% sure about this problem though)
(2) The first condition tells is that x < 1 but does not tell us anything beyond that so insufficient
The second condition tells that x > 0. But still in sufficient
Combining them yields 0 < x < 1 which is sufficient hence C
(3) Well tossed three times and lands the same side is the same as HHH or TTT so the probability is (1/2) * (1/2) * (1/2) + (1/2)* (1/2) * (1/2) = 1/4
(4) Ans is D because the total pay for the worker is 5x + 50 (x + x + 5...X + 20). Now the first condition compares two pays and we can solve x from that and hence obtain total pay
Same thing with second condition too so both are independently sufficient
(1) The arrangement is of the form
G B G
______
| |
______
B G B
So the guys can sit in 3! ways and the girls can sit in 3! ways and hence total num of ways = 3!*3! i.e. 36
(I am not 100% sure about this problem though)
(2) The first condition tells is that x < 1 but does not tell us anything beyond that so insufficient
The second condition tells that x > 0. But still in sufficient
Combining them yields 0 < x < 1 which is sufficient hence C
(3) Well tossed three times and lands the same side is the same as HHH or TTT so the probability is (1/2) * (1/2) * (1/2) + (1/2)* (1/2) * (1/2) = 1/4
(4) Ans is D because the total pay for the worker is 5x + 50 (x + x + 5...X + 20). Now the first condition compares two pays and we can solve x from that and hence obtain total pay
Same thing with second condition too so both are independently sufficient
200 or 800. It don't matter no more.
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Hey astacio
I saw that u scored 540 in GMAT ,i just wanted to know what was the break-up
and do u feel any similarity between GMATPrep exams and the actual
gmat???
I have been scoring in the same range!!!
Just curious
I saw that u scored 540 in GMAT ,i just wanted to know what was the break-up
and do u feel any similarity between GMATPrep exams and the actual
gmat???
I have been scoring in the same range!!!
Just curious