Statement (1) doesn't say that the range of the NUMBERS is 6, it says that the range of the REMAINDERS is 6.
So, even though we have 7 different numbers, we could have duplicate remainders.
Consider the set:
{7, 14, 21, 28, 35, 42, 48}
The biggest remainder is 6 (48/7 is 6rem6), the others all have rem0, so range=6.
The sum of the remainders is 0+0+0+0+0+0+6 = 6
Now consider the set:
{6, 13, 20, 27, 34, 41, 42}
The biggest remainder is 6 (each of the 1st 6 terms has rem6) and the smallest is 0, so the range=6.
However, the sum of the remainders is 0+6+6+6+6+6+6 = 36
We get two different answers to the question, therefore statement (1) is insufficient.
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