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2017 OG 356

This topic has 2 expert replies and 0 member replies
Anitochka Newbie | Next Rank: 10 Posts Default Avatar
Joined
01 Aug 2017
Posted:
4 messages

2017 OG 356

Post Mon Aug 21, 2017 8:17 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    If x and y are integers, is x>y?

    1) x+y>0
    2) y^x<0

    Answer: C

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    Post Mon Aug 21, 2017 1:28 pm
    Hi AbeNeedsAnswers,

    We're told that X and Y are integers. We're asked if X > Y. This is a YES/NO question. We can solve it with a mix of Number Properties and TESTing VALUES.

    1) X+Y > 0

    With this Fact, we know that at least one of the two variables is positive.
    IF.... X = 1, Y = 0 then the answer to the question is YES.
    IF.... X = 0, Y = 1 then the answer to the question is NO.
    Fact 1 is INSUFFICIENT

    2) Y^X < 0

    With this Fact, we know that Y CANNOT be positive (since a positive raised to any integer power is a positive). Thus, Y MUST be NEGATIVE and X must be ODD (since raising a negative to an EVEN power will end in a positive result).

    IF.... X = 1, Y = -1 then the answer to the question is YES.
    IF.... X = -3, Y = -1 then the answer to the question is NO.
    Fact 2 is INSUFFICIENT

    Combined, we know that there must be at least one positive value and that Y must be negative. By extension, that means that X MUST be positive - and the answer to the question is ALWAYS YES.
    Combined, SUFFICIENT

    Final Answer: C

    GMAT assassins aren't born, they're made,
    Rich

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    Post Mon Aug 21, 2017 9:03 pm
    Anitochka wrote:
    If x and y are integers, is x>y?

    1) x+y>0
    2) y^x<0

    Answer: C
    Hi Anitochka,

    Given: x and y are integers;
    To find: is x > y?

    Statement 1: x + y > 0

    => x > -y

    Case 1: Say y = -2, then x = a positive number greater than |y|, say, 3, thus, x > y, the asnwer is Yes.
    Case 2: Say y = 2, then x = -1, thus, x < y, the asnwer is No.

    No unique answer. Insufficient!

    Statement 2: y^x < 0

    Since a base with an exponent is a negative number, we can draw two results, one, y is negative and x is an odd integer.

    Since x can be any negative number greater than, equal to, or less than y, we cannot compare x and y. Insufficient!

    Statement 1 & 2:

    From Statement 2, we know that y is a negative number and from Statement 1, we know that x is a positive number (refer Case 1), thus x > y. Sufficient!

    The correct answer: C

    Hope this helps!

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