Before 3 years, dog A's age was 4times of dog B's age and after 4 years, dog A's age will be 3times of dog B's age. What is the difference of dog A's age and dog B's now?
A. 36
B. 42
C. 54
D. 60
E. 64
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Before 3 years, dog A’s age was 4times of dog B’s age an
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(Though the question never says they're still alive, raising all sorts of deep philosophical question regarding whether one can continue to age after death.)regor60 wrote:A is the Methuselah of dogs apparently A
Double-check your work on this one. (I'm assuming the question means "Three years ago, A's age was 4 times that of B, and four years from now, A's age will be 3 times that of B.)
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A-3=4(B-3) and A+4=3(B+4), B=17 and A=59. Hence, the correct answer is B.
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yes read too fastDavidG@VeritasPrep wrote:(Though the question never says they're still alive, raising all sorts of deep philosophical question regarding whether one can continue to age after death.)regor60 wrote:A is the Methuselah of dogs apparently A
Double-check your work on this one. (I'm assuming the question means "Three years ago, A's age was 4 times that of B, and four years from now, A's age will be 3 times that of B.)
- DavidG@VeritasPrep
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(You're in good company.)regor60 wrote:yes read too fastDavidG@VeritasPrep wrote:(Though the question never says they're still alive, raising all sorts of deep philosophical question regarding whether one can continue to age after death.)regor60 wrote:A is the Methuselah of dogs apparently A
Double-check your work on this one. (I'm assuming the question means "Three years ago, A's age was 4 times that of B, and four years from now, A's age will be 3 times that of B.)