If the mean of set S is 20, what is the median of set S ?

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If the mean of set S is 20, what is the median of set S ?

1. In set S there are as many numbers larger than 20 as there are numbers smaller than 20.
2. All numbers in set S are even integers.

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by MartyMurray » Fri Feb 24, 2017 12:17 pm
Statement 1: In set S there are as many numbers larger than 20 as there are numbers smaller than 20.

This answer choice is tricky. It seems to point to 20 being the median. However, we can use as an example any set that matches the parameters of both the question and this answer choice. We can also make the examples fit Statement 2, if possible, by using all even numbers.

First lets make the median 20.

Example 1: (10, 20, 30)

Mean: 20 Median: 20

Now let's seek to shift the numbers so that the mean is 20, but the median, which is halfway between the two middle values is not 20. We can do this by using four numbers and placing the inner two and outer two to create a mean of 20, while the mean of the middle two, i.e. the median, is not 20. To get a mean of 20, we just need four numbers that add up to 80. We can move them around many ways, seeking to generate at least two different medians.

Example 2: (0, 10, 30, 40)

Mean: 20 Median: (10 + 30)/2 = 20

Example 3: (0, 0, 30, 50)

Mean: 20 Median: (30 + 0)/2 = 15

Two different medians.

Insufficient.

Statement 2: All numbers in set S are even integers.

We already used this parameter in all examples used for Statement 1.

Insufficient.

Statements Combined:

We combined the statements when creating examples for Statement 1.

Insufficient.

The correct answer is E.
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by Brent@GMATPrepNow » Sat Feb 25, 2017 6:44 am
Mo2men wrote:If the mean of set S is 20, what is the median of set S ?

1. In set S there are as many numbers larger than 20 as there are numbers smaller than 20.
2. All numbers in set S are even integers.
Target question: What is the median of set S?

Given: The mean of set S is 20

SCAN the two statements . . . they seem pretty weak. So, let's TEST some values and jump straight to....

Statements 1 and 2 combined
There are several sets that satisfy BOTH statements. Here are two:
Case a: set S = {0, 20, 20, 40}. In this case, the median = (20 + 20)/2 = 20
Case b: set S = {0, 0, 22, 58}. In this case, the median = (0 + 22)/2 = 11
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer: E

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by [email protected] » Sat Feb 25, 2017 11:02 am
Hi Mo2men,

When you're told nothing about the individual numbers in a Set, then it's almost always easiest to TEST VALUES (and think about how the individual numbers could be 'near' or 'far' from the average).

We're told that the MEAN of a Set is 20. We're asked what the MEDIAN of that Set is?

1) In set S there are as many numbers larger than 20 as there are numbers smaller than 20.

IF... the set is...
{20, 20} then the median is 20.
{10, 19, 23, 28} then the median is 21.
Fact 1 is INSUFFICIENT

2) All numbers in set S are even integers.

IF... the set is...
{20, 20} then the median is 20.
{16, 22, 22} then the median is 22.
Fact 2 is INSUFFICIENT

Combined, we know...
There are as many numbers larger than 20 as there are numbers smaller than 20.
All numbers in set S are even integers.

IF... the set is...
{20, 20} then the median is 20.
{14, 16, 22, 28} then the median is 19.
Combined, INSUFFICIENT

Final Answer: E

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