At a certain company, two-seventh of the managers attended the company's annual meeting, and one-half of them were females. If one-tenth of the managers who did not attend the annual meeting were females, what fractional part of the total number of managers were males?
Solution from the book:-
No. of managers who did attend the annual meeting = 2/7
Females = 1/2 x 2/7 = 1/7
Males = 1/2 x 2/7 = 1/7
No. of managers who did not attend the annual meeting = 1-2/7 = 5/7
Females = 1/10 x 5/7 = 1/14
Males = 9/10 x 5/7 = 9/14
Total No. of Male Managers = 1/7+9/14=2/14+9/14=11/14
So, the answer is 11/14.
My workings:-
No. of managers who did attend annual meeting = 2/7m
Females = 1/2 x 2/7m = 1/7m
Males = Since female is 1/7m so male should be 1/7
No.of managers who did not attend the annual meeting = 5/7(remaining balance as 2/7 of the managers
attended the company's annual meeting)
Females = 1/10m x 5/7 = 1/14m
Males = 13/14m(remaining balance after deducting
1/14m of females)
Total No. of male managers = 1/7+13/14=2/14+13/14=15/14
So, my answer is 15/14.
M = managers
However, my answer is wrong. What is wrong with my workings and understanding here?
Thank you, guys.
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- anuprajan5
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Shanice,
You have got all the steps right except for this step:
Males = 13/14m(remaining balance after deducting
You need to deduct males from the managers who did not attend, not from 1.
Therefore - Male managers that did not attend = 5/7 - 1/14(females that did not attend) = 9/14
Therefore total male managers = 1/7 (first part that attended from your answer) + 9/14 = 11/14
Regards
Anup
You have got all the steps right except for this step:
Males = 13/14m(remaining balance after deducting
You need to deduct males from the managers who did not attend, not from 1.
Therefore - Male managers that did not attend = 5/7 - 1/14(females that did not attend) = 9/14
Therefore total male managers = 1/7 (first part that attended from your answer) + 9/14 = 11/14
Regards
Anup
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This is an EITHER/OR group question.shanice wrote:At a certain company, two-seventh of the managers attended the company's annual meeting, and one-half of them were females. If one-tenth of the managers who did not attend the annual meeting were females, what fractional part of the total number of managers were males?
Every manager is EITHER male OR female.
Every manager EITHER attended OR did not.
For an EITHER/OR group problem, use a GROUP GRID to organize the data.
Let the total number of managers = the LCM of the denominators in the problem (7,2,10) = 70.
Fill in the grid step-by-step.
Two-seventh of the managers attended the company's annual meeting, and one-half of them were females.
One-tenth of the managers who did not attend the annual meeting were females._______________M________F_______Total
A:_____________10______10________20
DA_______________________________50
total:_____________________________70
Males/total = 55/70 = 11/14._______________M________F_______Total
A:_____________10______10________20
DA____________ 45______5_________50
total:__________ 55_____15_________70
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- tisrar02
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My way I did this was as follows:
2/7 attended the meeting. 1/2 of them were females. 1/10 of those who did not attend were females.
Let the total number of managers =14
4/14 attended and 2/14 were females.
Meaning that 10/14 did not attend.
1/10 of those who did not attend were female so 1 female... Total number of females would be: 1/14+2/14=3/14
Number of males then would be 14/14-3/14= 11/14
Hope this helps.
I usually look at what the fractions are and then do my workings based on them.
2/7 attended the meeting. 1/2 of them were females. 1/10 of those who did not attend were females.
Let the total number of managers =14
4/14 attended and 2/14 were females.
Meaning that 10/14 did not attend.
1/10 of those who did not attend were female so 1 female... Total number of females would be: 1/14+2/14=3/14
Number of males then would be 14/14-3/14= 11/14
Hope this helps.
I usually look at what the fractions are and then do my workings based on them.
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