Practice Exam 1 - GMAT Prep - Algebra

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 97
Joined: Mon Aug 04, 2014 5:39 pm
Thanked: 1 times
Followed by:2 members

Practice Exam 1 - GMAT Prep - Algebra

by lucas211 » Thu May 26, 2016 6:36 am
Hello BTG

Would like to know if my approach to the following question is correct:

Image


1) we multiply out the right side to get the equation: xy+z = xy + xz
2) we subtract xy from both sides to get z = xz
3) from here we see, that z = xz, either x have to be one or z have to be "0".

Is this the correct approach?

Thanks in advance :-)

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Thu May 26, 2016 6:49 am
If xy+z = x(y+z) which of the following must be true?

A. x = 0 and Z = 0
B. x = 1 and y = 1
B. y = 1 and z = 0
D. x = 1 or y = 0
E. x = 1 or Z = 0
The key word here is must.
So, for example, consider answer choice A. While it's possible that x = 0 and z = 0, it need not be the case.
For example, x=1, y=1 and z=1 is a solution to the equation. So, this eliminates A.

The solution . . .
Given: xy+z = x(y+z)
Expand: xy+z = xy + xz
Subtract xy from both sides: z = xz
Rearrange: xz - z = 0
Factor: z(x-1) = 0

This tells us that z = 0 or x = 1
Answer: E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pm
Location: Palo Alto, CA
Thanked: 2867 times
Followed by:511 members
GMAT Score:800

by [email protected] » Thu May 26, 2016 9:15 am
Hi lucas211,

There's a discussion of this question here:

https://www.beatthegmat.com/must-be-true-qs-t278003.html

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image

GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pm
Location: East Bay all the way
Thanked: 625 times
Followed by:119 members
GMAT Score:780

by Matt@VeritasPrep » Thu May 26, 2016 2:28 pm
Your approach is dead on! Great job.

Senior | Next Rank: 100 Posts
Posts: 40
Joined: Wed Aug 30, 2017 6:48 pm

by danielle07 » Sun Sep 03, 2017 1:38 pm
Hi, How did you come up for the word "must"? Thanks

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 2095
Joined: Tue Dec 04, 2012 3:22 pm
Thanked: 1443 times
Followed by:247 members

by ceilidh.erickson » Mon Sep 04, 2017 8:19 am
danielle07 wrote:Hi, How did you come up for the word "must"? Thanks
It's written in the question: "which of the following MUST be true?" With such a question, we can eliminate any answer that does not HAVE to be true.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education

Site Admin
Posts: 28
Joined: Wed Aug 30, 2017 10:11 pm

by Admin1 » Mon Sep 04, 2017 10:13 am
xy + z = x (y + z)
xy + z = xy + xz (Distributive property)
xy + z - xy = xy + xz - xy (Subtracting xy on both sides)
z = xz (Simplify)
z - xz = xz - xz (Subtracting xz on both sides)
z - xz = 0 (Simplify)
z (1 - x) = 0 (Factor out z)
Either z = 0 or
1 - x = 0 => x = 1
Therefore, x = 1 or z = 0.
Option E must be correct.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 7241
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members
lucas211 wrote:
Thu May 26, 2016 6:36 am
Hello BTG

Would like to know if my approach to the following question is correct:

Image


1) we multiply out the right side to get the equation: xy+z = xy + xz
2) we subtract xy from both sides to get z = xz
3) from here we see, that z = xz, either x have to be one or z have to be "0".

Is this the correct approach?

Thanks in advance :-)
Simplifying, we have:

xy + z = xy + xz

z = xz

xz - z = 0

z(x - 1) = 0

z = 0 or x = 1

Answer: E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage