What is the largest prime factor of the expression 3^8 − 2^12?
A. 2
B. 3
C. 5
D. 17
E. 29
OA E
Source: Veritas Prep
What is the largest prime factor of the expression 3^8 − 2
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Hi All,
We're asked to find the LARGEST prime factor of the expression 3^8 - 2^12. Certain Quant questions ultimately come down to 'rewriting' information that you've been given. By rewriting 3^8 and 2^12 as "squared" terms, we'll have a 'difference of squares', which is a Classic Quadratic pattern in Algebra.
3^8 = 9^4 = 81^2
2^12 = 4^6 = 64^2
Thus, we have...
81^2 - 64^2 =
(81 - 64)(81 + 64) =
(17)(145) =
(17)(5)(29)
The largest prime factor is 29.
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
We're asked to find the LARGEST prime factor of the expression 3^8 - 2^12. Certain Quant questions ultimately come down to 'rewriting' information that you've been given. By rewriting 3^8 and 2^12 as "squared" terms, we'll have a 'difference of squares', which is a Classic Quadratic pattern in Algebra.
3^8 = 9^4 = 81^2
2^12 = 4^6 = 64^2
Thus, we have...
81^2 - 64^2 =
(81 - 64)(81 + 64) =
(17)(145) =
(17)(5)(29)
The largest prime factor is 29.
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
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There's a difference of squares "hiding" in the expression 3^8 − 2^12BTGmoderatorDC wrote:What is the largest prime factor of the expression 3^8 − 2^12?
A. 2
B. 3
C. 5
D. 17
E. 29
OA E
Source: Veritas Prep
That is 3^8 − 2^12 = (3^4)² − (2^6)²
We know that: x² - y² = (x + y)(x - y)
So, we get: (3^4)² − (2^6)² = (3^4 + 2^6)(3^4 - 2^6)
= (81 + 64)(81 - 64)
= (145)(17)
= (5)(29)(17)
The greatest prime factor is 29
Answer: E
Cheers,
Brent
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A general rule:
Given x^(even power) - y^(even power), where x and y are distinct positive integers, we can always simplify by applying the difference of two squares.
Each time we apply the difference of two squares to the expression in blue, the exponents are reduced by 1/2.
For example:
x� - y� = (x� + y²)(x� - y²) = (x� + y²)(x² + y¹)(x² - y¹)
Given x^(even power) - y^(even power), where x and y are distinct positive integers, we can always simplify by applying the difference of two squares.
Each time we apply the difference of two squares to the expression in blue, the exponents are reduced by 1/2.
For example:
x� - y� = (x� + y²)(x� - y²) = (x� + y²)(x² + y¹)(x² - y¹)
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We see that the expression 3^8 - 2^12 is a difference of squares. Thus, we have:BTGmoderatorDC wrote:What is the largest prime factor of the expression 3^8 − 2^12?
A. 2
B. 3
C. 5
D. 17
E. 29
3^8 - 2^12 = (3^4 + 2^6)(3^4 - 2^6) = (3^4 + 2^6)(3^2 + 2^3)(3^2 - 2^3)
3^4 + 2^6 = 81 + 64 = 145 = 5 x 29
3^2 + 2^3 = 9 + 8 = 17
3^2 - 2^3 = 9 - 8 = 1
So 3^8 - 2^12 = 5 x 29 x 17, and the largest prime factor is 29.
Answer: E
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