Hello,
Can you please help with this problem?
Tickets to a play cost $10 for children and $25 for adults. If 100 tickets were sold, were more adult tickets sold than children's tickets?
1) The average revenue per ticket was $18
2) The revenue from ticket sales exceeded $1750
OA: D
Thanks for your valuable time and help.
Best Regards,
Sri
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Weighted Averages
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gmattesttaker2
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# of children tickets = cgmattesttaker2 wrote:Hello,
Tickets to a play cost $10 for children and $25 for adults. If 100 tickets were sold, were more adult tickets sold than children's tickets?
1) The average revenue per ticket was $18
2) The revenue from ticket sales exceeded $1750
# of adult tickets = a
a+c = 100
Total revenue = 10*c + 25*a
If equal tickets were sold, then the revenue would be = 10*50 + 25*50 = $1750
From this we can conclude that if a>c, then revenue > $1750
Rephrased question : was the revenue > $1750
Statement 1:
avg revenue per ticket = revenue / # of tickets sold
=> total revenue = 18*100 = 1800 > 1750
Hence the statement is sufficient
Statement 2:
revenue > $1750
It answers our question
Hence the statement is sufficient
The correct answer is D
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GMATGuruNY
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Statement 1: The average revenue per ticket was $18.gmattesttaker2 wrote:Hello,
Can you please help with this problem?
Tickets to a play cost $10 for children and $25 for adults. If 100 tickets were sold, were more adult tickets sold than children's tickets?
1) The average revenue per ticket was $18
2) The revenue from ticket sales exceeded $1750
OA: D
Thanks for your valuable time and help.
Best Regards,
Sri
The average cost (18) is closer to the cost of an adult ticket (25) than to the cost of a children's ticket (10).
Thus, the number of adult tickets sold must have been greater than the number of children's tickets sold.
SUFFICIENT.
Statement 2: The revenue from ticket sales exceeded $1750.
Plug in the THRESHOLD: 50 of each type of ticket sold.
50(10) + 50(25) = 1750.
The equation above implies the following: for the total revenue to have EXCEEDED 1750, a greater number of the more expensive tickets -- the ADULT tickets -- must have been sold.
SUFFICIENT.
The correct answer is D.
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Is it possible for the average to be 18$???
If that is the case then 25a+10c = 1800 (since total tickets was 100)
and a+c =100 (a=number of adult tickets and c is number of children tickets)
a and c will have non integer values. That is not possible
If that is the case then 25a+10c = 1800 (since total tickets was 100)
and a+c =100 (a=number of adult tickets and c is number of children tickets)
a and c will have non integer values. That is not possible
GMATGuruNY wrote:Statement 1: The average revenue per ticket was $18.gmattesttaker2 wrote:Hello,
Can you please help with this problem?
Tickets to a play cost $10 for children and $25 for adults. If 100 tickets were sold, were more adult tickets sold than children's tickets?
1) The average revenue per ticket was $18
2) The revenue from ticket sales exceeded $1750
OA: D
Thanks for your valuable time and help.
Best Regards,
Sri
The average cost (18) is closer to the cost of an adult ticket (25) than to the cost of a children's ticket (10).
Thus, the number of adult tickets sold must have been greater than the number of children's tickets sold.
SUFFICIENT.
Statement 2: The revenue from ticket sales exceeded $1750.
Plug in the THRESHOLD: 50 of each type of ticket sold.
50(10) + 50(25) = 1750.
The equation above implies the following: for the total revenue to have EXCEEDED 1750, a greater number of the more expensive tickets -- the ADULT tickets -- must have been sold.
SUFFICIENT.
The correct answer is D.
Is it possible for the average to be 18$???
If that is the case then 25a+10c = 1800 (since total tickets was 100)
and a+c =100 (a=number of adult tickets and c is number of children tickets)
a and c will have non integer values. That is not possible
