(1) oes the decimal equivalent of P/Q, where P and Q are positive integers, contain only
a finite number of nonzero digits?
(1) P>Q
(2) Q=8
I chose B, why the hell is E
(2)if x^2+y^2=1, is x+y=1?
(1)xy=0
(2)y=0
I chose D, why the hell is E again,
can some one explain me????
Two questions, pls help explain
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- sl750
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B looks good in problem 1. I don't know why the hell it is E
For problem 2
X^2+Y^2 = 1 can be written as (X+Y)^2 -2XY = 1
Statement 1
XY=0, that gives us two values for X+Y = -1 or 1. Insufficient
Statement 2
Y=0, that gives us two values for X = -1 or 1. Therefore two solutions for X+Y. Insufficient
Statement 1 and 2
Insufficient, as we have two solutions for X+Y
For problem 2
X^2+Y^2 = 1 can be written as (X+Y)^2 -2XY = 1
Statement 1
XY=0, that gives us two values for X+Y = -1 or 1. Insufficient
Statement 2
Y=0, that gives us two values for X = -1 or 1. Therefore two solutions for X+Y. Insufficient
Statement 1 and 2
Insufficient, as we have two solutions for X+Y
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If there is a PRIME number other than 2 of 5 in the denominator of a fraction, then it will be a non-finite decimal (for example 1/3 = .333333).
We need to know what P/Q reduces to in order to answer.
1) INSUFFICIENT. If P = 2 and Q = 1, then we get 2/1 = 2, or if P = 4 and Q = 3, we get 4/3 = 1.3333, then the answer is no.
2) SUFFICIENT. The answer is B, IMO.
Check out older threads on this Q: https://www.beatthegmat.com/set24-q-26-p ... 71622.html
We need to know what P/Q reduces to in order to answer.
1) INSUFFICIENT. If P = 2 and Q = 1, then we get 2/1 = 2, or if P = 4 and Q = 3, we get 4/3 = 1.3333, then the answer is no.
2) SUFFICIENT. The answer is B, IMO.
Check out older threads on this Q: https://www.beatthegmat.com/set24-q-26-p ... 71622.html
Vivian Kerr
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Thank you for all the "thanks" and "follows"!