If \(n\) is a positive integer, the sum of the integers from

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If \(n\) is a positive integer, the sum of the integers from 1 to \(n\), inclusive, equals \(\frac{n(n+1)}{2}\). Which of the following equals the sum of the integers from 1 to 2\(n\), inclusive?

A. \(n(n+1)\)
B. \(\frac{n(2n+1)}{2}\)
C. \(n(2n+1)\)
D. \(2n(n+1)\)
E. \(2n(2n+1)\)

OA C

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by Scott@TargetTestPrep » Fri May 10, 2019 4:37 pm
AAPL wrote:GMAT Paper Tests

If \(n\) is a positive integer, the sum of the integers from 1 to \(n\), inclusive, equals \(\frac{n(n+1)}{2}\). Which of the following equals the sum of the integers from 1 to 2\(n\), inclusive?

A. \(n(n+1)\)
B. \(\frac{n(2n+1)}{2}\)
C. \(n(2n+1)\)
D. \(2n(n+1)\)
E. \(2n(2n+1)\)

OA C
We just need to replace n in the formula by 2n; so the sum of the integers from 1 to 2n, inclusive is 2n(2n + 1)/2 = n(2n + 1).

Answer: C

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