The number line shown contains three points R, S, and T

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The number line shown contains three points R, S, and T, whose coordinates have absolute values r, s, and t, respectively. Which of the following equals the average (arithmetic mean) of the coordinates of the points R, S, and T?

A. s
B. s + t - r
C. (r - s - t)/3
D. (r + s + t)/3
E. (s + t - r)/3

[spoiler]OA=E[/spoiler]

Source: Official Guide

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by GMATGuruNY » Sun Apr 28, 2019 2:35 am
Gmat_mission wrote:Image

The number line shown contains three points R, S, and T, whose coordinates have absolute values r, s, and t, respectively. Which of the following equals the average (arithmetic mean) of the coordinates of the points R, S, and T?

A. s
B. s + t - r
C. (r - s - t)/3
D. (r + s + t)/3
E. (s + t - r)/3
Let R=-3, S=3 and T=6, implying that r=|-3|=3, s=|3|=3, and t=|6|=6.
Average of R, S, and T = (-3+3+6)/3 = 2.
The correct answer must yield 2 when r=3, s=3 and t=6.
Only E works:
(s + t - r)/3 = (3+6-3)/3 = 6/3 = 2

The correct answer is E.
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by Scott@TargetTestPrep » Wed May 01, 2019 4:17 pm
Gmat_mission wrote:Image

The number line shown contains three points R, S, and T, whose coordinates have absolute values r, s, and t, respectively. Which of the following equals the average (arithmetic mean) of the coordinates of the points R, S, and T?

A. s
B. s + t - r
C. (r - s - t)/3
D. (r + s + t)/3
E. (s + t - r)/3

[spoiler]OA=E[/spoiler]

Source: Official Guide
We can let R, S, and T be the actual values. Thus, we want to determine the value of (R + S + T)/3. Since S and T are positive, S = s and T = t. However, since R is negative, R = -r. Thus, the average becomes:

(-r + s + t)/3

(s + t - r)/3

Answer: E

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