Manhattan GMAT
Students are in clubs as follows: Science-20, Drama-30, and Band-12. No student is in all three clubs, but 8 are in both Science and Drama, 6 are in both Science and Band, and 4 are in Drama and Band. How many different students are in at least one of the three clubs?
A. 36
B. 38
C. 42
D. 44
E. 48
OA D.
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Students are in clubs as follows: Science-20, Drama-30, and
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GMATGuruNY
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When we count the total in Science, the total in Drama, and the total in Band, any students in exactly two of the clubs are counted TWICE.AAPL wrote:Manhattan GMAT
Students are in clubs as follows: Science-20, Drama-30, and Band-12. No student is in all three clubs, but 8 are in both Science and Drama, 6 are in both Science and Band, and 4 are in Drama and Band. How many different students are in at least one of the three clubs?
A. 36
B. 38
C. 42
D. 44
E. 48
Thus, we must SUBTRACT these students so that they are not double counted:
Total = Science + Drama + Band - (exactly 2 clubs) = 20 + 30 + 12 - (8+6+4) = 44.
The correct answer is D.
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I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
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Scott@TargetTestPrep
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We can use the following formula:AAPL wrote:Manhattan GMAT
Students are in clubs as follows: Science-20, Drama-30, and Band-12. No student is in all three clubs, but 8 are in both Science and Drama, 6 are in both Science and Band, and 4 are in Drama and Band. How many different students are in at least one of the three clubs?
A. 36
B. 38
C. 42
D. 44
E. 48
OA D.
n(At least one set) = n(A) + n(B) + n(C) - n(A and B) - n(A and C) - n(B and C) + n(A and B and C)
n(At least one set) = 20 + 30 + 12 - 8 - 6 - 4 + 0
n(At least one set) = 44
Answer: D
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