[GMAT math practice question]
If x=0.2, then what is the value of x^3-1/x-1?
A. 1.2
B. 1.22
C. 1.24
D. 1.44
E. 2.22
If x=0.2, then what is the value of x^3-1/x-1?
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- Max@Math Revolution
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Some spaces and/or brackets would definitely help here.Max@Math Revolution wrote:[GMAT math practice question]
If x=0.2, then what is the value of x^3-1/x-1?
A. 1.2
B. 1.22
C. 1.24
D. 1.44
E. 2.22
Do you mean x^3 - 1/x - 1 or x^3 - 1/(x - 1) or (x^3 - 1)/(x - 1)??
Cheers,
Brent
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((0.2)^3 - 1)/(0.2 - 1)Max@Math Revolution wrote:[GMAT math practice question]
If x=0.2, then what is the value of x^3-1/x-1?
A. 1.2
B. 1.22
C. 1.24
D. 1.44
E. 2.22
(0.008 - 1)/(-0.8)
(-0.992)/(-0.8) = 1.24
Alternate solution:
The formula for factoring the difference of cubes is (x^3 - 1) = (x - 1)(x^2 + x +1). We can use that fact to simplify (x^3 - 1)/(x - 1) = x^2 + x + 1. Therefore, when x = 0.2, we have:
(0.2)^2 + 0.2 + 1 = 0.04 + 0.2 + 1 = 1.24
Answer: C
- Max@Math Revolution
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=>
$$\frac{x^3-1}{x-1}=\frac{\left(x-1\right)\left(x^2+x+1\right)}{x-1}=x^2+x+1$$
Plugging in x = 0.2 yields
x^2+x+1 = (0.2)^2 + (0.2) + 1 = 0.04 + 0.2 + 1 = 1.24
Therefore, the answer is C.
Answer: C
$$\frac{x^3-1}{x-1}=\frac{\left(x-1\right)\left(x^2+x+1\right)}{x-1}=x^2+x+1$$
Plugging in x = 0.2 yields
x^2+x+1 = (0.2)^2 + (0.2) + 1 = 0.04 + 0.2 + 1 = 1.24
Therefore, the answer is C.
Answer: C
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