In the figure above, polygon N has been partially covered by

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Veritas Prep

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In the figure above, polygon N has been partially covered by a piece of paper. How many sides does N have?

1) x + y = 45
2) N is a regular polygon

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by fskilnik@GMATH » Sun Dec 09, 2018 7:01 am

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AAPL wrote:Veritas Prep

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In the figure above, polygon M has been partially covered by a piece of paper. How many sides does M have?

1) x + y = 45
2) M is a regular polygon
$$? = N\,\,\left( {{\rm{number}}\,\,{\rm{of}}\,\,{\rm{sides}}\,\,{\rm{of}}\,\,{\rm{polygon}}\,\,M} \right)$$
All measures are in degrees.

Each statement alone is insufficient, as PROVEN by the Geometric Bifurcations shown below:



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$$\left( {1 + 2} \right)\,\,\,\,\left\{ \matrix{
\,\left( 1 \right)\,\,\,\, \Rightarrow \,\,\,A = 180 - \left( {x + y} \right) = 135 \hfill \cr
\,\left( 2 \right)\,\,\,\, \Rightarrow \,\,A = {{\left( {N - 2} \right) \cdot 180} \over N} \hfill \cr} \right.\,\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = N = {\rm{unique}}\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left( {\rm{C}} \right)$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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