Is triangle ABC an acute angled triangle? 1) [m]c^2 < a^

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Is triangle ABC an acute angled triangle?

1) [m]c^2 < a^2 + b^2[/m] where a, b and c are sides of triangle ABC
2) Sides of the triangle ABC have lengths 5, 6 and 7

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by fskilnik@GMATH » Wed Oct 31, 2018 12:53 pm

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GMATinsight wrote:Is triangle ABC an acute angled triangle?

1) [m]c^2 < a^2 + b^2[/m] where a, b and c are sides of triangle ABC
2) Sides of the triangle ABC have lengths 5, 6 and 7

Source: www.GMATinsight.com
All angles are measured in degrees.
$${\rm{all}}\,\,\Delta ABC\,\,{\rm{internal}}\,\,{\rm{angles}}\,\,\mathop < \limits^? \,\,\,{90}$$

(We assume c is the length of the side that is opposite to the internal angle ACB, etc.)

$$\left( 1 \right)\,\,\,\,{c^2} < {a^2} + {b^2}\,\,\,\, \Rightarrow \,\,\,\,\,\angle ACB < 90\,\,\,\, \Rightarrow \,\,\,\,{\rm{INSUFF}}.\,$$

Image


$$\left( 2 \right)\,\,\,5,6,7\,\,\,\,\, \Rightarrow \,\,\,\,\,\Delta ABC\,\,{\rm{unique}}\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\Delta ABC\,\,{\rm{internal}}\,\,{\rm{angles}}\,\,{\rm{are}}\,\,{\rm{uniquely}}\,\,{\rm{known}}\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{\rm{SUFF}}.\,\,\,\,\,\,\,\,\,$$

POST-MORTEM:
$${7^2} < {5^2} + {6^2}\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\max \,\,\,\Delta ABC\,\,{\rm{internal}}\,\,{\rm{angle}}\,\,\,\, < \,\,90\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle $$


This solution follows the notations and rationale taught in the GMATH method.

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Fabio.
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by Jay@ManhattanReview » Wed Oct 31, 2018 11:51 pm

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GMATinsight wrote:Is triangle ABC an acute-angled triangle?

1) c^2 < a^2 + b^2, where a, b and c are sides of triangle ABC
2) Sides of the triangle ABC have lengths 5, 6 and 7

Source: www.GMATinsight.com
Let's take each statement one by one.

1) c^2 < a^2 + b^2, where a, b and c are sides of triangle ABC.

=> /_ACB < 90º and if /_ABC < 90º and /_BAC < 90º, the answer is Yes.

However, if a^2 ≥ c^2 + b^2, we have /_BAC ≥ 90º, the answer is No.

No unique answer. Insufficient.

2) Sides of the triangle ABC have lengths 5, 6 and 7.

Given the sides 5, 6, and 7, we know that the largest of the angles would be the one opposite the side with length 7.

Since 5^2 + 6^2 < 7^2 => 25 + 36 < 49 => 61 < 49, we have the largest angle of ABC < 90º, thus, ABC is an acute angled triangle.

Sufficient.

The correct answer: B

Hope this helps!

-Jay
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