If a sequence of positive odd integers has six terms containing a total of thirteen digits, then the first term is a multiple of?
A. 11
B. 13
C. 15
D. 17
E. 19
If a sequence of positive odd integers has six terms contain
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 187
- Joined: Tue Sep 13, 2016 12:46 am
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
This problem is invalid.alanforde800Maximus wrote:If a sequence of positive odd integers has six terms containing a total of thirteen digits, then the first term is a multiple of?
A. 11
B. 13
C. 15
D. 17
E. 19
Since the only conditions are that six terms must be positive and odd and have a total of 13 digits, an infinite number of cases are possible.
Here are two options:
11, 13, 15, 17, 19, 101
13, 11, 15, 17, 19, 101
Since the sequence does not have to be ascending, any of the answer choices could be a divisor of the first term.
Ignore this problem.
What is the source?
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
-
- Newbie | Next Rank: 10 Posts
- Posts: 3
- Joined: Mon Jun 22, 2015 7:25 am
I agree the problem is unsolvable by the way it's stated. However, I think he meant to say "positive consecutive odd integers" instead of "positive odd integers".
GMATGuruNY wrote:This problem is invalid.alanforde800Maximus wrote:If a sequence of positive odd integers has six terms containing a total of thirteen digits, then the first term is a multiple of?
A. 11
B. 13
C. 15
D. 17
E. 19
Since the only conditions are that six terms must be positive and odd and have a total of 13 digits, an infinite number of cases are possible.
Here are two options:
11, 13, 15, 17, 19, 101
13, 11, 15, 17, 19, 101
Since the sequence does not have to be ascending, any of the answer choices could be a divisor of the first term.
Ignore this problem.
What is the source?