Cameron can paint a room in c hours. Cameron and Mackenzie..

[AAPL]

Cameron can paint a room in c hours. Cameron and Mackenzie, working together, can paint the room in d hours. In terms of c and d, how long in hours would it take Mackenzie, working alone, to paint the room?

$$A.\ 2d-c$$
$$B.\ \frac{c+d}{cd}$$
$$C.\ \frac{c-d}{cd}$$
$$D.\ \frac{cd}{c+d}$$
$$E.\ \frac{cd}{c-d}$$

The OA is E.

Can I solve it as follow,

Cameron's rate:
$$Cam's\ rate=\frac{1}{c}$$
Cameron and Mackenzie's rate when working together:
$$Combined\ rate=\frac{1}{d}$$
Mackenzie's rate:
$$Mack's\ rate=\frac{1}{d}-\frac{1}{c}$$
Finally, Mackenzie's time:
$$T(Mackenzie)=\frac{1}{\frac{1}{d}-\frac{1}{c}}=\frac{1}{\frac{c-d}{cd}}=\frac{cd}{c-d}$$
Is there a strategic approach to this question? Can any experts help, please?

[mbawisdom]

Cameron can paint a room in c hours. Cameron and Mackenzie, working together, can paint the room in d hours. In terms of c and d, how long in hours would it take Mackenzie, working alone, to paint the room?

$$A.\ 2d-c$$
$$B.\ \frac{c+d}{cd}$$
$$C.\ \frac{c-d}{cd}$$
$$D.\ \frac{cd}{c+d}$$
$$E.\ \frac{cd}{c-d}$$

The OA is E.

Can I solve it as follow,

Cameron's rate:
$$Cam's\ rate=\frac{1}{c}$$
Cameron and Mackenzie's rate when working together:
$$Combined\ rate=\frac{1}{d}$$
Mackenzie's rate:
$$Mack's\ rate=\frac{1}{d}-\frac{1}{c}$$
Finally, Mackenzie's time:
$$T(Mackenzie)=\frac{1}{\frac{1}{d}-\frac{1}{c}}=\frac{1}{\frac{c-d}{cd}}=\frac{cd}{c-d}$$
Is there a strategic approach to this question? Can any experts help, please?

I like the way you approached it. In long form I would solve it as follows:

Rate = Work/Time

(1) Rc = 1/c
(2) Rc + Rd = 1/d
(3) Rd = 1/T

Put (1) and (3) into 2:
1/c + 1/T = 1/d
1/T = 1/d - 1/c
1/T = (c - d)/cd
T = cd/(c-d)

Answer is E.

[[email protected]]

Hi AAPL,

We're told that Cameron can paint a room in C hours and Cameron and Mackenzie, working TOGETHER, can paint the room in D hours. We're asked, in terms of C and D, for how long (in hours) would it take Mackenzie, working alone, to paint the room.

This is an example of a "Work Formula" question - when you have two entities working together on a task, you can use the following formula to determine how long it will take the two entities to complete the task:

(X)(Y)/(X+Y) = time to complete the task (where X and Y are the two times it takes the individuals to complete the task when working alone). We can use this formula - and TEST VALUES - to get the correct answer.

IF...
Cameron takes 3 hours to paint the room and
Mackenzie takes 6 hours to paint the room, then...
it would take (3)(6)/(3+6) = 18/9 = 2 hours for the two of them to paint the room together.

Thus, we're looking for an answer that equals 6 when we plug C=3 and D=2 into it. There's only one answer that matches...

Final Answer: E

GMAT assassins aren't born, they're made,
Rich

[Jeff@TargetTestPrep]

Cameron can paint a room in c hours. Cameron and Mackenzie, working together, can paint the room in d hours. In terms of c and d, how long in hours would it take Mackenzie, working alone, to paint the room?

$$A.\ 2d-c$$
$$B.\ \frac{c+d}{cd}$$
$$C.\ \frac{c-d}{cd}$$
$$D.\ \frac{cd}{c+d}$$
$$E.\ \frac{cd}{c-d}$$

We are given that Cameron can paint a room in c hours. Since rate = work/time, Cameron's rate is 1/c. We are also given that, working together, Cameron and Mackenzie can paint the room in d hours. If we let m = the time it takes Mackenzie to paint the room alone, we can create the following equation:

1/c + 1/m = 1/d

We need to determine how long it would take Mackenzie to paint the room by herself, so we need to isolate m.

We can start by multiplying the entire equation by cmd:

md + cd = cm

cd = cm - md

cd = m(c - d)

cd/(c - d) = m

Answer: E