James and Logan are taking batting practice. If their

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Princeton Review

James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are \(x\) and \(y\), respectively, then what is the probability that James will not hit a homerun but Logan will?

A. \(x - xy\)
B. \(x - y^2\)
C. \(y - xy\)
D. \(\frac{y}{x}\)
E. \(\frac{1}{x} - y\)

OA C

[Brent@GMATPrepNow]

Princeton Review

James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are \(x\) and \(y\), respectively, then what is the probability that James will not hit a homerun but Logan will?

A. \(x - xy\)
B. \(x - y^2\)
C. \(y - xy\)
D. \(\frac{y}{x}\)
E. \(\frac{1}{x} - y\)

OA C

If P(James hits home run) = x, then P(James does NOT hit home run) = 1-x
Given: P(Logan hits home run) = y

So, P(James will not hit a home run AND Logan hits a home run) = P(James will not hit a home run) X P(Logan hits a home run)
= (1-x) X (y)
= y - yx

Answer: C

Cheers,
Brent

[Scott@TargetTestPrep]

Princeton Review

James and Logan are taking batting practice. If their individual probabilities of hitting a homerun are \(x\) and \(y\), respectively, then what is the probability that James will not hit a homerun but Logan will?

A. \(x - xy\)
B. \(x - y^2\)
C. \(y - xy\)
D. \(\frac{y}{x}\)
E. \(\frac{1}{x} - y\)

OA C

The probability that James will not hit a homerun but Logan will is (1 - x)(y) = y - yx.

Answer: C