[GMAT math practice question]9.27
xyz=2, what is the value of x/(xy+x+2) + y/(yz+y+1) + 2z/(zx+2z+2)?
A.1
B.2
C.3
D. 4
E. 5
xyz=2, what is the value of x/(xy+x+2) + y/(yz+y+1) + 2z/(zx
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- Max@Math Revolution
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=>
x/(xy+x+2) + y/(yz+y+1) + 2z/(zx+2z+2)
= x/(xy+x+2) + xy/(xyz+xy+x) + 2xyz/(x^2yz+2xyz+2xy)
= x/(xy+x+2) + xy/(2+xy+x) + 2*2/(2x+2*2+2xy)
= x/(xy+x+2) + xy/(xy+x+2) + 2*2/2[(xy+x+2)]
= (xy+x+2)/(xy+x+2) = 1.
Therefore, A is the answer.
Answer: A
x/(xy+x+2) + y/(yz+y+1) + 2z/(zx+2z+2)
= x/(xy+x+2) + xy/(xyz+xy+x) + 2xyz/(x^2yz+2xyz+2xy)
= x/(xy+x+2) + xy/(2+xy+x) + 2*2/(2x+2*2+2xy)
= x/(xy+x+2) + xy/(xy+x+2) + 2*2/2[(xy+x+2)]
= (xy+x+2)/(xy+x+2) = 1.
Therefore, A is the answer.
Answer: A
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