[GMAT math practice question]
The figure shows that AB is parallel to FE. What is ∠ABC + ∠BCD + ∠CDE + ∠DEF?
A. 380
B. 440
C. 540
D. 600
E. 720
The figure shows that AB is parallel to FE. What is ∠ABC
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- Max@Math Revolution
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Draw two lines GK and HO parallel to AB and FE as follows.
Then we have ∠ABC + ∠BCG = 180°, ∠GCD + ∠CDH = 180°, ∠HDE + ∠DEF = 180°, and the pairs of two angles are supplementary, respectively.
∠ABC + ∠BCD + ∠CDE + ∠DEF = ∠ABC + (∠BCG + ∠GCD) + (∠CDH + ∠HDE) + ∠DEF = (∠ABC + ∠BCG) + (∠GCD + ∠CDH) + (∠HDE + ∠DEF) = 180° + 180° + 180° = 540°,
Therefore, C is the answer.
Answer: C
Then we have ∠ABC + ∠BCG = 180°, ∠GCD + ∠CDH = 180°, ∠HDE + ∠DEF = 180°, and the pairs of two angles are supplementary, respectively.
∠ABC + ∠BCD + ∠CDE + ∠DEF = ∠ABC + (∠BCG + ∠GCD) + (∠CDH + ∠HDE) + ∠DEF = (∠ABC + ∠BCG) + (∠GCD + ∠CDH) + (∠HDE + ∠DEF) = 180° + 180° + 180° = 540°,
Therefore, C is the answer.
Answer: C
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