Problem Solving

[BTGmoderatorRO]

If cement, gravel and sand are to be mixed in 7:10:13 and 8 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.

A. 35 $$\frac{7}{8}$$
B. 36
C. 34 $$\frac{2}{7}$$
D. 34 $$\frac{5}{7}$$
E. 34 $$\frac{6}{7}$$

OA is C
How can I start to solve this, I don't really have a clue. Can an Expert come to my help urgently? thanks

[Jeff@TargetTestPrep]

If cement, gravel and sand are to be mixed in 7:10:13 and 8 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.

A. 35 $$\frac{7}{8}$$
B. 36
C. 34 $$\frac{2}{7}$$
D. 34 $$\frac{5}{7}$$
E. 34 $$\frac{6}{7}$$

We have the ratio of cement : gravel : sand = 7x : 10x : 13x, for a total of 30x.

Since 8 tons of cement is available we have:

8 = 7x

8/7 = x

So the total mixture that can be produced is 30 * 8/7 = 240/7 = 34 2/7.

Answer; C