There are 6 stores in town that had a total of 20 visitors

[AAPL]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

The OA is C.

1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).

Has anyone another strategic approach to solve this PS question? Regards!

[Jay@ManhattanReview]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

The OA is C.

1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).

This is perfect.

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Vienna | Kuala Lumpur | Sydney | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Has anyone another strategic approach to solve this PS question? Regards!

[Jay@ManhattanReview]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

The OA is C.

1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).

This is perfect.

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Vienna | Kuala Lumpur | Sydney | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Has anyone another strategic approach to solve this PS question? Regards!

[Jay@ManhattanReview]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

The OA is C.

1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).

This is perfect.

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Vienna | Kuala Lumpur | Sydney | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Has anyone another strategic approach to solve this PS question? Regards!

[Jay@ManhattanReview]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

The OA is C.

1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).

This is perfect.

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Vienna | Kuala Lumpur | Sydney | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Has anyone another strategic approach to solve this PS question? Regards!

[Jay@ManhattanReview]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

The OA is C.

1 Person ---> 1 store = 1 visit. (as the question says that some people visited more than 1 store, meaning that there was at least 1 person who visited 1 store)
6 People ---> 2 store = 12 visit.
Remaining 3 People, to maximize the number of stores visited by an individual, we minimize the store visited by other 2.
So,
2 people ---> 1 store = 2 visit.
Total visit remaining = 20 -1-12-2 = 5 visit. (which is done by the last person).

This is perfect.

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Vienna | Kuala Lumpur | Sydney | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Has anyone another strategic approach to solve this PS question? Regards!

[Scott@TargetTestPrep]

There are 6 stores in town that had a total of 20 visitors on a particular day. However, only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited?

A. 6
B. 8
C. 5
D. 9
E. 2

We must recognize that when the problem says there are 20 visitors, it doesn't mean there are 20 people (since it later says there are only 10 people). It really means, if a person visited one store, then he or she is considered as one visitor. However, if that person visited two stores, then he or she is considered as two visitors since each of the two stores he or she visited will consider him or her as one visitor. Similarly, if he or she visited three stores, then he or she is considered as three visitors and so on.

Since 6 people visited exactly two stores each, then they are considered to be 12 visitors. Thus we have 20 - 12 = 8 visitors left for the remaining 10 - 6 = 4 people. In order to maximize the number of stores visited for one person, we must minimize the number of stores visited for the other 3 individuals. Thus, if those 3 people each visited exactly 1 store, then they are considered to be 3 visitors. Thus, we have 8 - 3 = 5 visitors left for the last person, which means he or she must have visited 5 stores.

Answer: C