In the coordinate plane, what is the distance between points (3,5) and (7,10)?
A) 3
B) 3√3
C) 2√5
D) √37
E) √41
Hey all, it seems to be not very hard problem,but I have trouble drawing it that's why I couldn't solve it at the first place. Thanks for help.
Correct answer isE
Coordinate plane
This topic has expert replies
-
- Junior | Next Rank: 30 Posts
- Posts: 18
- Joined: Thu Oct 13, 2011 11:08 pm
- vk_vinayak
- Legendary Member
- Posts: 502
- Joined: Tue Jun 03, 2008 11:36 pm
- Thanked: 99 times
- Followed by:21 members
No need to draw in this case. If you know the forumla, you can calculatethe distance between two pointselenaelena wrote:In the coordinate plane, what is the distance between points (3,5) and (7,10)?
A) 3
B) 3√3
C) 2√5
D) √37
E) √41
Hey all, it seems to be not very hard problem,but I have trouble drawing it that's why I couldn't solve it at the first place. Thanks for help.
Correct answer isE
Distance between (x1, y1) and (x2, y2) is SQRT( (y2-y1)^2 + (x2-x1)^2))
Therefore distance between (3,5) and (7,10) is SQRT((5^2) + (4^2) ) = SQRT(41). Choose E.
- VK
I will (Learn. Recognize. Apply)
I will (Learn. Recognize. Apply)
-
- Junior | Next Rank: 30 Posts
- Posts: 18
- Joined: Thu Oct 13, 2011 11:08 pm
Thanks a lot for your reply. I will memorize this formula for my future use.vk_vinayak wrote:No need to draw in this case. If you know the forumla, you can calculatethe distance between two pointselenaelena wrote:In the coordinate plane, what is the distance between points (3,5) and (7,10)?
A) 3
B) 3√3
C) 2√5
D) √37
E) √41
Hey all, it seems to be not very hard problem,but I have trouble drawing it that's why I couldn't solve it at the first place. Thanks for help.
Correct answer isE
Distance between (x1, y1) and (x2, y2) is SQRT( (y2-y1)^2 + (x2-x1)^2))
Therefore distance between (3,5) and (7,10) is SQRT((5^2) + (4^2) ) = SQRT(41). Choose E.
- neelgandham
- Community Manager
- Posts: 1060
- Joined: Fri May 13, 2011 6:46 am
- Location: Utrecht, The Netherlands
- Thanked: 318 times
- Followed by:52 members
Graphical Solution :
Let (3,5) be point A and (7,10) be point B. When plotted on a graph, the line AB looks like the one in the attachement below.
From the graph, AC = 4 Units and BC = 5 units. Since triangle ACB is a right angled triangle,
AB^2 = AC^2 + CB^2 (Pythagorean theorem)
AB^2 = 4^2 + 5^2 = 16 + 25 = 41
Distance between the points = AB = √41
Let (3,5) be point A and (7,10) be point B. When plotted on a graph, the line AB looks like the one in the attachement below.
From the graph, AC = 4 Units and BC = 5 units. Since triangle ACB is a right angled triangle,
AB^2 = AC^2 + CB^2 (Pythagorean theorem)
AB^2 = 4^2 + 5^2 = 16 + 25 = 41
Distance between the points = AB = √41
- Attachments
-
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
-
- Master | Next Rank: 500 Posts
- Posts: 271
- Joined: Tue May 22, 2012 3:22 am
- Thanked: 7 times
- Followed by:3 members
-
- Junior | Next Rank: 30 Posts
- Posts: 18
- Joined: Thu Oct 13, 2011 11:08 pm
Thanks for this picture and very easy solution!neelgandham wrote:Graphical Solution :
Let (3,5) be point A and (7,10) be point B. When plotted on a graph, the line AB looks like the one in the attachement below.
From the graph, AC = 4 Units and BC = 5 units. Since triangle ACB is a right angled triangle,
AB^2 = AC^2 + CB^2 (Pythagorean theorem)
AB^2 = 4^2 + 5^2 = 16 + 25 = 41
Distance between the points = AB = √41
GMAT/MBA Expert
- Jeff@TargetTestPrep
- GMAT Instructor
- Posts: 1462
- Joined: Thu Apr 09, 2015 9:34 am
- Location: New York, NY
- Thanked: 39 times
- Followed by:22 members
We can use the distance formula:elenaelena wrote:In the coordinate plane, what is the distance between points (3,5) and (7,10)?
A) 3
B) 3√3
C) 2√5
D) √37
E) √41
d = √[(y2 - y1)^2 + (x2 - x1)^2]
d = √[(10 - 5)^2 + (7 - 3)^2]
d = √(5^2 + 4^2)
d = √(25 + 16) = √41
Answer: E
Jeffrey Miller
Head of GMAT Instruction
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews