Before 3 years, dog A’s age was 4times of dog B’s age an

[Max@Math Revolution]

Before 3 years, dog A's age was 4times of dog B's age and after 4 years, dog A's age will be 3times of dog B's age. What is the difference of dog A's age and dog B's now?
A. 36
B. 42
C. 54
D. 60
E. 64

*An answer will be posted in 2 days.

[regor60]

A is the Methuselah of dogs apparently A

[DavidG@VeritasPrep]

A is the Methuselah of dogs apparently A

(Though the question never says they're still alive, raising all sorts of deep philosophical question regarding whether one can continue to age after death.)

Double-check your work on this one. (I'm assuming the question means "Three years ago, A's age was 4 times that of B, and four years from now, A's age will be 3 times that of B.)

[Max@Math Revolution]

A-3=4(B-3) and A+4=3(B+4), B=17 and A=59. Hence, the correct answer is B.

[regor60]

A is the Methuselah of dogs apparently A

(Though the question never says they're still alive, raising all sorts of deep philosophical question regarding whether one can continue to age after death.)

Double-check your work on this one. (I'm assuming the question means "Three years ago, A's age was 4 times that of B, and four years from now, A's age will be 3 times that of B.)

yes read too fast

[DavidG@VeritasPrep]

A is the Methuselah of dogs apparently A

(Though the question never says they're still alive, raising all sorts of deep philosophical question regarding whether one can continue to age after death.)

Double-check your work on this one. (I'm assuming the question means "Three years ago, A's age was 4 times that of B, and four years from now, A's age will be 3 times that of B.)

yes read too fast

(You're in good company.)