if X^2 + 5Y = 49, is Y an Integer?
1) 1 < X < 4
2) X^2 is an integer.
The answer is E? I think it should be C, can some one explain why E?
The following is my reason for C)
From 1) X could be 2, 3, 3/2 etc. If X is 2 or 3 then Y is an integer but if 3/2 then it is not so, 1) is not sufficient.
From 2) not sufficient
From 1 and 2. X^2 is integer then X should be integer so possible values are 2,3. For these 2 values Y is integer - so sufficient.
Kaplan DS
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- jayhawk2001
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If X^2 is an integer, X need not necessarily be an integer. Take X^2 = 3.gmatme wrote: From 1 and 2. X^2 is integer then X should be integer so possible values are 2,3. For these 2 values Y is integer - so sufficient.
X = sqrt(3) [ positive root ] which is not an integer.
Hence E
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here's how i look at it:
1) X can be any value between 1 and 4, not inclusive. let's assume X=1.1. plugging that into the question stem gives us 1.21+5Y=49. pretty obvious that Y is not an integer. let's say X=2. then we have 4+5Y=49. Y then is an integer. so we have determined both "yes" and "no" to the question. 1) is not sufficient. rule out A and D.
2) cover 1) up momentarily and just consider 2). X^2 is an integer, but X is not necessarily an integer. in the example given by jayhawk2001, the sqrt of 3 is roughly 1.73. point is, unless we know what X is, X^2 can be any integer (1, 5, 85, etc.), which gives us both "yes" and "no" to the question if Y is an integer. thus, 2) is not sufficient, so we rule out B. but 2) also indirectly addresses combining statements 1) and 2). since X^2 is part of the question and we know that X^2 IS an integer, we get different values for Y when X^2 takes on different values. thus, 1) and 2) are both insufficient. the answer is E.
1) X can be any value between 1 and 4, not inclusive. let's assume X=1.1. plugging that into the question stem gives us 1.21+5Y=49. pretty obvious that Y is not an integer. let's say X=2. then we have 4+5Y=49. Y then is an integer. so we have determined both "yes" and "no" to the question. 1) is not sufficient. rule out A and D.
2) cover 1) up momentarily and just consider 2). X^2 is an integer, but X is not necessarily an integer. in the example given by jayhawk2001, the sqrt of 3 is roughly 1.73. point is, unless we know what X is, X^2 can be any integer (1, 5, 85, etc.), which gives us both "yes" and "no" to the question if Y is an integer. thus, 2) is not sufficient, so we rule out B. but 2) also indirectly addresses combining statements 1) and 2). since X^2 is part of the question and we know that X^2 IS an integer, we get different values for Y when X^2 takes on different values. thus, 1) and 2) are both insufficient. the answer is E.