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cubicle_bound_misfit
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Number of ways of chosing 2 expressions out of 4: C(4,2) = 6
The only pair that results in an expression of the type x^2 - (by)^2 is: x+y, x-y.
Rest all have the term xy.
Therefore, p = (# of favorable outcomes)/(# of total outcomes) = 1/6
The only pair that results in an expression of the type x^2 - (by)^2 is: x+y, x-y.
Rest all have the term xy.
Therefore, p = (# of favorable outcomes)/(# of total outcomes) = 1/6
